Are Parallel Circuits Affected When One Bulb Goes Out?

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Discussion Overview

The discussion revolves around the behavior of parallel circuits, specifically addressing the scenario where one light bulb goes out while another remains lit. Participants explore the implications of this situation on current, voltage, and resistance within the circuit.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions why the remaining bulb does not get brighter when one bulb goes out, suggesting that they are in a parallel configuration.
  • Another participant challenges the expectation that a bulb with a given wattage would get brighter, emphasizing that the voltage across it remains constant.
  • A participant discusses the current flowing through bulbs in parallel circuits and poses questions about the implications of changing the number of bulbs on current flow.
  • One participant introduces the concept of impedance (Z) and suggests that the circuit may not be a simple parallel circuit, or that the remaining bulb's impedance may have changed, leading to the same brightness.
  • Another participant reiterates the question of why the current remained the same despite the change in the circuit configuration.
  • One participant concludes that the current in the leg of the circuit with the remaining bulb has stayed the same, while the other leg has zero current, implying a drop in total current.

Areas of Agreement / Disagreement

Participants express differing views on the behavior of current and brightness in the circuit, with no consensus reached on the underlying reasons for the observations made regarding the bulbs.

Contextual Notes

There are unresolved questions regarding the assumptions about circuit behavior, the definitions of impedance, and the implications of changing the number of loads in parallel.

iScience
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my living room light switch controls two lights. one of the light bulbs just went out.
since the switch controlled two bulbs, aren't they in parallel? so then why didn't the light bulb that is still on get any brighter?
 
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Why would you expect a bulb with a given wattage get brighter?
 
dlgoff said:
Why would you expect a bulb with a given wattage get brighter?

indeed.

consider that it still has the same voltage across it 110V 240V ( whatever in your country)

so say 100W globe, 110V what is the current flowing through it ?

2 x 100W globes in parallel with 110V across them, what is the current through each of them ?

3 100W globes in parallel with 110V across them, what is the current through each of them ?

when you have worked that out ... do you see where its leading ?

cheers
Dave
 
I thought the power rating tells you what the device was made for. regardless of what current and voltage you put across the device, the device has its inherent Z value, whether or not its dynamic (a function).if the light in parallel goes out, all the sudden there is a change in Z(eq). Remaining at the same brightness implies either...

1.) The circuit is not just a simple parallel circuit.

or..

2.) the light bulb has somehow increased its Z value.there is definitely an initial change in Z(eq); what i'd like to know is what happened such that the current remained the same?
 
so say 100W globe, 110V what is the current flowing through it ?

2 x 100W globes in parallel with 110V across them, what is the current through each of them ?

3 100W globes in parallel with 110V across them, what is the current through each of them ?

when you have worked that out ... do you see where its leading ?

$$I=\frac{P}{V}=\frac{V}{R_{eq}}=V(\frac{1}{R_1+R_2+...})$$

still dependent on the number of loads in parallel. i still don't get it
 
iScience said:
there is definitely an initial change in Z(eq); what i'd like to know is what happened such that the current remained the same?

why do you think current has remained the same?
 
because the second light bulb (one that's still on) didn't change in brightness
 
iScience said:
because the second light bulb (one that's still on) didn't change in brightness

right, the current in that leg of the parallel circuit has stayed the same. But the other leg now has zero current, so the total current in the light fixture must have dropped in half.
 
ohhh... i see .

okay thanks!
 

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