A Are quantum fields real objects in space?

  • #101
DarMM said:
Does this not ignore those who are objectively handsome/beautiful such as us Advisors?

Maybe that's why I became a mentor - my mirror tells me different every morning - my shaver even started to shut down when I used it. Disconcerting actually - but I eventually sorted the shaver out - took it to the place I bought it from who puled it to pieces - even my whiskers are against me - they clogged it up despite me cleaning it every day - it turns out you have to pull it to pieces and get rid of bits in the things that spin and foul it.

Thanks
Bill
 
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  • #102
Demystifier said:
OK, now you answered my question so I can proceed. Essentially, you identify the particle with the corresponding state in the Hilbert space. The particle is the state in the Hilbert space. Fine, now let us see what are the consequences of this statement.
No, not at all. The particle is not the state. Take for example classical mechanics. The particle is described by six numbers. The particle is not a six-tple of numbers.
DarMM said:
I don't understand, if the fields are not taken as really existing, but just taken as mathematical method for generating basis elements for an observable algebra, then they're not real objects in space right? It's directly related to it by saying they're not real. I genuinely don't understand, it seems fairly clearly related.
You are using the same word in two different ways, which causes the confusion. The fields are the physical objects that exists in space (and time), which we want to study. The operators, which you also call fields, are the mathematical description, and of course they don't exist, it is meaningless to say that they do.
Demystifier said:
If you think that it is not easy to make sense of interpretation in which particle does not exist until measured, I perfectly agree with you. One needs to work hard to make sense of it. As a result of such a hard work, I wrote the paper http://de.arxiv.org/abs/1112.2034
But, there is no such interpretation. At least so far you havn't shown one. In all your citations there wasn't even a hint that particles/fields don't exist. And you didn't answer my question. If the particle doesn't exist, do we have empty space?
 
  • #103
bhobba said:
Maybe that's why I became a mentor
Well you mentors are on a whole other level, not merely good looking but so much so that us mortals can only grasp it dimly.
 
  • #104
martinbn said:
You are using the same word in two different ways, which causes the confusion. The fields are the physical objects that exists in space (and time), which we want to study. The operators, which you also call fields, are the mathematical description, and of course they don't exist, it is meaningless to say that they do.
No, I'm not using it in two sense. In Haag's description there is nothing physically real obeying field equations, hence there are no physically real fields. There is only the algebra of local observables. Fields only appear as one method of constructing the algebra.

Other methods exist:
https://arxiv.org/abs/1005.2656
 
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  • #105
DarMM said:
Well you mentors are on a whole other level, not merely good looking but so much so that us mortals can only grasp it dimly.

Yea right. We are so good looking we have an area we have to look at to discuss posts that need looking at. I am sure its meant to age us so whatever looks we have are soon gone - assuming they are there to begin with. The things we do so people have a reliable source of science/math/engineering :-p:-p:-p:-p:-p:-p:-p. Seriously it is nice helping people with science stuff in a different way than just contributing to threads - I really enjoy it.

Thanks
Bill
 
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  • #106
bhobba said:
Yea right. We are so good looking we have an area we have to look at to discuss posts that need looking at. I am sure its meant to age us so whatever looks we have are soon gone - assuming they are there to begin with.
No sympathy from me, you know it takes six of us Advisors to carry you lot in one of your golden palanquins?

(Alright I'll stop dragging the thread off topic now! :wink:)
 
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  • #107
DarMM said:
No, I'm not using it in two sense. In Haag's description there is nothing physically real obeying field equations, hence there are no physically real fields. There is only the algebra of local observables. Fields only appear as one method of constructing the algebra.
I think the problem in communication comes in the use of the phrase "physically real". Here is the question, is there something out there or do we have empty space? If there is something, we need to give it a name, say a particle or a field. That is what is physically real, that is what exists. That thing can be described mathematically by say a mathematical field, that obeys the equations. Of course the mathematical object doesn't exist, but the there is something that does, which is also called a field.

I don't understand why this whole busyness is so hard to understand. Even with my poor writing skills, it should be clear.
 
  • #108
martinbn said:
No, not at all. The particle is not the state. Take for example classical mechanics. The particle is described by six numbers. The particle is not a six-tple of numbers.
But whatever mathematical property follows from those six numbers, we say it is a property of the particle itself. For instance, if the particle equations of classical mechanics have a property of nonlocality, as e.g. in Newton theory in gravity, we say that particles themselves obey nonlocal laws.

So in that sense, do you agree that your view of particle in QM implies non-locality? If not, why not?

martinbn said:
And you didn't answer my question. If the particle doesn't exist, do we have empty space?
In a sense, yes. We have the wave function, but not a physical object associated it. This is like "classical mechanics" in which we have the Hamiltonian ##H(x,p)##, but not a particle with the trajectory ##X(t)##.
 
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  • #109
Demystifier said:
But whatever mathematical property follows from those six numbers, we say it is a property of the particle itself. For instance, if the particle equations of classical mechanics have a property of nonlocality, as e.g. in Newton theory in gravity, we say that particles themselves obey nonlocal laws.

So in that sense, do you agree that your view of particle in QM implies non-locality? If not, why not?
Wait, what has that to do with the discussion? Locality or non-locality is a separate question. The question is are the fields/particles real in space?
Demystifier said:
In a sense, yes. We have the wave function, but not a physical object associated it. This is like "classical mechanics" in which we have the Hamiltonian H(x,p)H(x,p), but not a particle with the trajectory X(t)X(t).
This seems very inconsistent. If we have empty space, then what is the difference between one particle and two? It's just empty space in both cases. In the example of classical mechanics what is the Hamiltonian of? How can you not have a particle?
 
  • #110
martinbn said:
I think the problem in communication comes in the use of the phrase "physically real". Here is the question, is there something out there or do we have empty space? If there is something, we need to give it a name, say a particle or a field.
In Haag and other versions of Copenhagen what is taken to exist are events in macroscopic objects like detection devices. Fields are simply tools used to assists in computing correlations between these events.

What actually does exist they are silent on. Though Bohr, Omnés and Haag take a similar view that the fundamentally stochastic nature of QM and results like Bell's theorem (obviously not in the case of Bohr) indicate a limit in the applicability of human mathematics to nature and thus the fundamental stuff is incomprehensible.

So the reason one has no hidden variables is because the "stuff" doesn't admit a mathematical description.

martinbn said:
That thing can be described mathematically by say a mathematical field, that obeys the equations
In this view the physically real things do not obey field equations.
 
  • #111
DarMM said:
In Haag and other versions of Copenhagen what is taken to exist are events in macroscopic objects like detection devices. Fields are simply tools used to assists in computing correlations between these events.

What actually does exist they are silent on. Though Bohr, Omnés and Haag take a similar view that the fundamentally stochastic nature of QM and results like Bell's theorem (obviously not in the case of Bohr) indicate a limit in the applicability of human mathematics to nature and thus the fundamental stuff is incomprehensible.

So the reason one has no hidden variables is because the "stuff" doesn't admit a mathematical description.
Ok, now I understand, and it is perfectly fine. My problem is not with what actually exists, but with atyy's claim that it doesn't exist. I did say earlier that in my impression Copenhagen is silent on the issue. Demistifier said that some versions are not silent and say that the particle/field doesn't exist.
DarMM said:
In this view the physically real things do not obey field equations.
Of course not. The baseball ball doesn't obey any equations. The functions that describe it obey the equations.
 
  • #112
martinbn said:
Wait, what has that to do with the discussion? Locality or non-locality is a separate question. The question is are the fields/particles real in space?
It's related, as seen e.g. in the EPR argument and the Bell theorem.
 
  • #113
martinbn said:
I think the problem in communication comes in the use of the phrase "physically real". Here is the question, is there something out there or do we have empty space?

We do give it a name EM fields etc. I explained why classically most physicists consider them real - they carry, via Noether, momentum and energy which generally physicists think of as real. It's of course a deep philosophical question if they are, but if you are commonsenseical you tend to go down that path. As Weinberg said in his article about Kuhn (I must be frank I am no fan of Kuhn, Popper is better, but even he doesn't quite capture it as Feynman does) when he talks about reality, and wants to be careful, he says - whatever that is. Its just that physically most think of things like energy and momentum as real - again using whatever conception of real they hold to. After all mass is a form of energy, so fields can in principle be converted to mass, and if you do not think of mass as real, again under whatever you think real is, you are in very strange territory indeed (Penrose may be in that very territory) - I think physicists will generally not go that far. Now if classical EM are real and they are a limit of EM QFT fields, it's hard to think exactly at what point in taking that limit it becomes real, so generally speaking most would think them real. Remember though a QFT field is a field of quantum operators and we know they have a very real aspect - the eigenvalues are the possible outcomes of observations - and observations are very real. Some say QM is incomplete because we do not know exactly what is an observation - but that is getting off topic.

Thanks
Bill
 
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  • #114
martinbn said:
Ok, now I understand, and it is perfectly fine. My problem is not with what actually exists, but with atyy's claim that it doesn't exist. I did say earlier that in my impression Copenhagen is silent on the issue. Demistifier said that some versions are not silent and say that the particle/field doesn't exist.

Of course not. The baseball ball doesn't obey any equations. The functions that describe it obey the equations.
Well more so, if there are no objects describing them that obey field or particle equations you cannot really call them particles or fields. I mean those terms really only mean "a thing described by particle/field theories". So there is "stuff" but it's not particles or fields.

I'm not saying I agree with this, but I do think @atyy's description is right.
 
  • #115
DarMM said:
Well more so, if there are no objects describing them that obey field or particle equations you cannot really call them particles or fields. I mean those terms really only mean "a thing described by particle/field theories". So there is "stuff" but it's not particles or fields.
That's just terminology, whether it is particles, fields or something else is secondary for this question. The point is that there is something.
DarMM said:
I'm not saying I agree with this, but I do think @atyy's description is right.
Well, he claims that there isn't anything according to Copenhagen. He doesn't say that there is something, which isn't fields, and the fields aren't real, they are mathematical descriptions of something real. He says that if no one measures there is nothing.
 
  • #116
martinbn said:
If we have empty space, then what is the difference between one particle and two?
When we perform the measurement (which for no-reality interpretations is a misnomer, one should rather call it the experiment), we hear one or two clicks in the detector. That's the difference.

martinbn said:
In the example of classical mechanics what is the Hamiltonian of? How can you not have a particle?
Mathematically it makes perfect sense to have a Hamiltonian as an object by its own. Physically, for a version of classical mechanics without particle trajectories see my https://link.springer.com/article/10.1007/s10702-006-1009-2
 
  • #117
martinbn said:
The point is that there is something.
The Bell theorem says that if there is something, then this something obeys nonlocal laws. And yet, if I remember correctly, in other threads you deny nonlocality. My point is that it is inconsistent to accept that both (i) there is something and (ii) this something obeys local laws.
 
  • #118
martinbn said:
But, there is no such interpretation. At least so far you havn't shown one. In all your citations there wasn't even a hint that particles/fields don't exist.
How about the following quotes of Mermin, taken from https://en.wikipedia.org/wiki/Relational_quantum_mechanics#History_and_development :
David Mermin has contributed to the relational approach in his "Ithaca interpretation."[8] He uses the slogan "correlations without correlata", meaning that "correlations have physical reality; that which they correlate does not", so "correlations are the only fundamental and objective properties of the world".

In the same paragraph on wikipedia:
The moniker "zero worlds"[9] has been popularized by Ron Garret[10] to contrast with the many worlds interpretation.
 
  • #119
The way I see Bell's theorem and the interpretive camps.

The assumptions of the theorem are:
  1. Ontological Framework Axioms (Single World, No RetroCausality, No Superdeterminism)
  2. Relativistic Causation, i.e. no physical effects that reach outside their relativistic light cone
  3. Common cause. That is some event can be considered the cause of other events, i.e. C is a common cause of A,B if there correlations would be absent without C
  4. Decorrelating Explanation. There is an event, conditioned on which the correlations between A,B vanish, hence it explains their correlation.
Non-Realist interpretations tend to drop number 4, that is they don't view the correlations in Bell's inequality as being explained by any event in spacetime. There can be causes (i.e. the device that prepares the Bell state), however that only allows the correlations to exist, it doesn't explain them.

Or more clearly, the preparation of the Bell state is necessary to find the correlations, but what actual achieves them is not a mechanistic (in the sense of admitting a mathematical description) process occurring in spacetime.
 
  • #120
martinbn said:
Well, he claims that there isn't anything according to Copenhagen. He doesn't say that there is something, which isn't fields, and the fields aren't real, they are mathematical descriptions of something real. He says that if no one measures there is nothing.

There is certainly nothing you are reading correctly.
 
  • #121
Demystifier said:
According to some versions of Copenhagen interpretation, the Moon does not exist when nobody looks at it. For instance, Wheeler said that “no phenomenon is a real phenomenon until it is an observed phenomenon.”

Regarding Wheeler’s statement, P. C. W. Davies and Julian R. Brown say in “The Ghost in the Atom: A Discussion of the Mysteries of Quantum Physics”:

It means that, on its own an atom or electron or whatever cannot be said to 'exist' in the full, common-sense, notion of the word.” (italics in the original)

Or, as N. David Mermin (in “Making Better Sense of Quantum Mechanics”) has recently read some of Bohr’s quotations:

Both quotations state that physics is not so much about phenomena, as it is about our experience of those phenomena.

What you term “moon” is first and foremost a mental image, which is in your mind and not in the external world, at the end an encodement of a set of potentialities or possible outcomes of measurements. The Copenhagens merely warn people not to mistake this map for the territory.
 
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  • #122
Lord Jestocost said:
The Copenhagen’s merely warn people not to mistake this map for the territory.
Actually, we have three things that should be distinguished:
1) The map (mathematical formalism of QM).
2) The territory (the physical objects existing irrespective of our observations).
3) Our vision of the territory (the measurement outcomes).
I view Copenhagen as a statement that we should talk seriously about 1) and 3), but not about 2). Realists, on the other hand, view 2) as the central object of research, while 1) and 3) are just the research tools.
 
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  • #123
martinbn said:
Well, he claims that there isn't anything according to Copenhagen.

I will not get into a discussion on what nothing means, form your own view of that, but clearly there is something under what most would think as 'something'. Consider a particle in a box and you measure its position. If there is no particle you will never - doesn't matter how many times you measure a position - you will never get an an answer. If there is a particle you will always get an answer. It modifies the usual idea of something somewhat - but most would say there is something there - we just do not know its properties until measured and can only predict probabilities. What's going on when not measured Copenhagen as far as I know from the various versions I have read says - we do not know - not there is nothing. Certainly the formalism doesn't say anything.

Thanks
Bill
 
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  • #124
Demystifier said:
1) The map (mathematical formalism of QM).
2) The territory (the physical objects existing irrespective of our observations).
3) Our vision of the territory (the measurement outcomes).

I, personally, would beware of restricting the "Territory" to "physical objects".
 
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  • #125
they are as real as anything.if it has an effect on any thing it is real
 
  • #126
bhobba said:
I will not get into a discussion on what nothing means, form your own view of that, but clearly there is something under what most would think as 'something'. Consider a particle in a box and you measure its position. If there is no particle you will never - doesn't matter how many times you measure a position - you will never get an an answer. If there is a particle you will always get an answer. It modifies the usual idea of something somewhat - but most would say there is something there - we just do not know its properties until measured and can only predict probabilities. What's going on when not measured Copenhagen as far as I know from the various versions I have read says - we do not know - not there is nothing. Certainly the formalism doesn't say anything.

Thanks
Bill
That is my view and understanding.
 
  • #127
Demystifier said:
Mathematically it makes perfect sense to have a Hamiltonian as an object by its own. Physically, for a version of classical mechanics without particle trajectories see my https://link.springer.com/article/10.1007/s10702-006-1009-2
I might take a look, but I am already skeptical. You are switching between the notions. The point was whether you can have a version without particles (without objects no matter the name), now you are talking about a version without particle trajectories.
Demystifier said:
The Bell theorem says that if there is something, then this something obeys nonlocal laws. And yet, if I remember correctly, in other threads you deny nonlocality. My point is that it is inconsistent to accept that both (i) there is something and (ii) this something obeys local laws.
I have no problem with "nonlocality" except for the name. I also don't see how Bell's theorem says that if there is something it obeys nonlocal laws! It says that if those things that exist out there posses quantities that have values at all times then the laws are nonlocal.
Demystifier said:
How about the following quotes of Mermin, taken from https://en.wikipedia.org/wiki/Relational_quantum_mechanics#History_and_development :
David Mermin has contributed to the relational approach in his "Ithaca interpretation."[8] He uses the slogan "correlations without correlata", meaning that "correlations have physical reality; that which they correlate does not", so "correlations are the only fundamental and objective properties of the world".
That is more of the same. The fact that spins of two particles are correlated and the sipns don't have values before measurements doesn't imply that there are no particles.
 
  • #128
atyy said:
There is certainly nothing you are reading correctly.
There is your chance to clear things up.
 
  • #129
martinbn said:
I have no problem with "nonlocality" except for the name. I also don't see how Bell's theorem says that if there is something it obeys nonlocal laws! It says that if those things that exist out there posses quantities that have values at all times then the laws are nonlocal.
Then we agree more than I thought. Since you are fine with nonlocality, can you just remind me what exactly do you not like about the Bohmian interpretation? It's important for this thread because Bohmian interpretation is made precisely with the intention to say what is real in space.
 
  • #130
martinbn said:
I have no problem with "nonlocality" except for the name. I also don't see how Bell's theorem says that if there is something it obeys nonlocal laws! It says that if those things that exist out there posses quantities that have values at all times then the laws are nonlocal.
Just for accuracy, that's not quite what it says. Possessing quantities at all times is the assumption technically called "Decorrelating explanation" in the assumptions of the theorem. One can retain it, but give up one of the other assumptions aside from locality.
 
  • #131
Demystifier said:
Then we agree more than I thought. Since you are fine with nonlocality, can you just remind me what exactly do you not like about the Bohmian interpretation? It's important for this thread because Bohmian interpretation is made precisely with the intention to say what is real in space.
I am fine with nonlicality in the sense in which QM is nonlocal. I am not fine with nonlocality when it means infinite speed of propagation. The main problem I have with BM is that it is very unclear (in fact quite confused) about the ontology of the wave function. Ah, and it is nonrelativistic.
 
  • #132
martinbn said:
I am fine with nonlicality in the sense in which QM is nonlocal. I am not fine with nonlocality when it means infinite speed of propagation.
In BM there is no infinite speed of propagation.

martinbn said:
The main problem I have with BM is that it is very unclear (in fact quite confused) about the ontology of the wave function.
You can think of wave function ##\psi(x,t)## in BM as something analogous to the principal function ##S(x,t)## in the Hamilton-Jacobi formulation of classical mechanics. I think it reduces the confusion a lot.

martinbn said:
Ah, and it is nonrelativistic.
That's a separate topic on which I was writing (on this forum and elsewhere) a lot.
 
  • #133
bhobba said:
...but clearly there is something under what most would think as 'something'.

One should add, however, that this 'something' cannot be objectified, so it's of inscrutanable nature.
 
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  • #134
The answer to the question in the title is clearly "No!" In general, a wavefunction is a function on configuration space, not physical space. When you have two particles, for instance, ##\psi(x_1, x_2, t)## is the probability amplitude of finding the first particle at location ##x_1## and the second particle at location ##x_2##. In contrast, a physical field (such as the electric field) gives a value at each point in physical space.

[edit]This is a poor response to the original question, which was about fields, not wave functions.

What I would say about fields is that in QM they are operators, not values.
 
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  • #135
Lord Jestocost said:
One should add, however, that this 'something' cannot be objectified, so it's of inscrutanable nature.

Of course - it has exactly the same status as Weinberg pointed out but his critics forgot he carefully qualified - reality. Such fundamental things are notoriously hard to pin down. Its just most people would say if every-time you measured position you got an answer you would say something is in there - what is meant by something - blackout.

Thanks
Bill
 
  • #136
stevendaryl said:
The answer to the question in the title is clearly "No!" In general, a wavefunction is a function on configuration space, not physical space. When you have two particles, for instance, ##\psi(x_1, x_2, t)## is the probability amplitude of finding the first particle at location ##x_1## and the second particle at location ##x_2##. In contrast, a physical field (such as the electric field) gives a value at each point in physical space.

The field has an operator-valued value at each point in physical space.
 
  • #137
stevendaryl said:
The answer to the question in the title is clearly "No!" In general, a wavefunction is a function on configuration space, not physical space. When you have two particles, for instance, ##\psi(x_1, x_2, t)## is the probability amplitude of finding the first particle at location ##x_1## and the second particle at location ##x_2##. In contrast, a physical field (such as the electric field) gives a value at each point in physical space.

That is true and got my like - but I think the OP was referring to the Quantum Fields of QFT which are quantum operators assigned to every point - not state AKA wave-functions. In QFT the state space is a fock space.

Thanks
Bill
 
  • #138
bhobba said:
That is true and got my like - but I think the OP was referring to the Quantum Fields of QFT which are quantum operators assigned to every point - not state AKA wave-functions. In QFT the state space is a fock space.

Yes. It's sort of confusing in quantum field theory that the field operators seems like noncommuting versions of the wave functions of non-relativistic quantum mechanics. They really are not analogous. There more like the position and momentum operators of non-relativistic quantum mechanics.
 
  • #139
atyy said:
The field has an operator-valued value at each point in physical space.

You're right. The OP was not talking about the wave function.
 
  • #140
The wavefunctions in QFT are of the form (in the Heisenberg picture):
$$\Psi(\phi), \quad \phi \in \mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right), \quad \Psi \in \mathcal{H} = \mathcal{L}^{2}\left(\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right),d\nu\right)$$
with ##\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right)## the space of tempered Schwarz distributions on a spacelike slice. Depending on the measure ##d\nu## the Hilbert space has a Fock decomposition. It doesn't for ##d > 1## for an interacting theory (without inifinite volume cutoff).
 
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  • #141
DarMM said:
The wavefunctions in QFT are of the form (in the Heisenberg picture):
$$\Psi(\phi), \quad \phi \in \mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right), \quad \Psi \in \mathcal{H} = \mathcal{L}^{2}\left(\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right),d\nu\right)$$
with ##\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right)## the space of tempered Schwarz distributions on a spacelike slice. Depending on the measure ##d\nu## the Hilbert space has a Fock decomposition.

Yes. In going from non-relativistic quantum mechanics to quantum field theory, I originally found it confusing because I thought of ##\phi## as the analogy for the nonrelativistic wave function, when it's actually ##\Psi##. The confusion is made worse by the fact that the Heisenberg equations for ##\phi## look (at least for free fields) like the Schrodinger equation for the single-particle wave function.
 
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  • #142
My personal view on this it's either field XOR particle..
The only time this appears to be untrue is when the two combined cause effect at the same time..
But in that case it's a field separate from the particle effect..
I think a lot of people mistake a field for a particle effect that they can't explain given current physics knowledge..

But in any case, when particles are involved it's not a field, and when it's a true field, it's not particles..
That's the annoying part..the particles do something we can only explain using field theories..
Hence it's called particle field, which in and by itself is a misnomer of sorts..

Anyways, that's my 10 cents..
 
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  • #143
ZMacZ said:
I think a lot of people mistake a field for a particle effect that they can't explain given current physics knowledge..

In QFT its all explained by the mathematics of the field - it has a form similar to the so called second quantization formulation, and hence quantum particles
https://pdfs.semanticscholar.org/2fb0/4475228ff385a44a16e3ba42b432d3bf5b17.pdf

That's how particles emerge from fields in QFT,

Thanks
Bill
 
  • #144
It is safe to say that both wave particle duality and the collapse of the wave function are not present when quantum mechanics is modeled precisely (particles are just waves which are localised, "collapsing" is the strong dependence of the state on the information that is available.
Roughly speaking a quantum state which is defined over both space and time expresses a state of knowledge. It is this state of knowledge which is affected by things such as the detection of a particle at a specific location. With a two slit experiment, the Schroedinger equation for a particle without any knowledge of a detector consists of a field which diffracts outwards from the two slits and exhibits interference. But once detected, the past locations of the particle are highly constrained to the two paths from the slits to the detection. If we knew in advance where the array of detectors were and the physics indicated that it was highly likely that one of the detectors would detect the particle, the correct wave function to express our state of knowledge before detection would be the sum of the ones after each of the individual possible detections (with some appropriate weights). [This notion is not part of the Copenhagen interpretation, and I have not seen it in an introductory text - it owes more to Feynman's viewpoint. The Copenhagen viewpoint seems to be based on a desire to retain causality in the evolution of the wave function as a physical field. An argument against this is that the wave function is a state of belief depending on some set of relevant information, and this remains true when the information is associated with things in the future of the wave function (such as the location of a set of detectors].
By contrast with the two wave functions associated with passing through one or other of the slits, these wave functions associated with distinct detections interfere with each other very little and add classically, like probabilities. The thing that makes the detections have this dramatic effect on the wave function is that the paths that end in a detection have very high probability for reasons which may be best expressed in terms of them being high entropy. This makes the contribution from other paths very small, unlike when the detectors are not there.
 
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  • #145
Elroch said:
It is safe to say that both wave particle duality and the collapse of the wave function are not present when quantum mechanics is modeled precisely (particles are just waves which are localised, "collapsing" is the strong dependence of the state on the information that is available.

I don't see how that interpretation of quantum probabilities is consistent with what we know about quantum mechanics.

If you pass unpolarized light through a polarizing filter, it comes out polarized in the direction corresponding to the filter orientation. Viewing this as a matter of acquiring information about the photons is certainly not complete. If you have three filters oriented at angle ##0^o##, ##45^o## and ##90^o##, 12.5% of the unpolarized photons (1/8 of them) will pass through all three filters. That can't possibly be a matter of just learning the pre-existing polarization of the photons, because it is impossible to have a photon that will pass through a filter at both 0 and 90 degrees. Passing through the filter changes the polarization of the photons. So it's not simply a matter of updating information.
 
  • #146
kith said:
Would you consider the quantum system itself to be real in Copenhagen?
The Copenhagen interpretation is more "real" because it's observable: Upon observation, all quantum possibilities collapse into one outcome. This has been tested with the double-slit experiment.
There's a problem though, and it has to do with the "quantum information paradox". Upon waveform collapse, the information about all of the other possible quantum states is lost, thus violating the conservation of information.
Everett's MWI offers a solution to this: All outcomes are equally real but exist in different branches of the multiverse, which we can not observe. The conservation of information states that information can not be destroyed but it does not mean it has to be accessible, so the MWI satisfies this.
 
  • #147
A. Neumaier said:
So the Moon (considered as a many-particle quantum object) is not real when nobody looks at it?
Oh it's real! The gravitational attraction is obvious, otherwise there would be drastic changes to tides if nobody looked at the moon.

You can think of the probability of a macroscopic object existing is equal to that the ~sum of the probabilities of enough particles being in the position they need to be to form the moon is essentially 100%.
 
  • #148
stevendaryl said:
I don't see how that interpretation of quantum probabilities is consistent with what we know about quantum mechanics.

If you pass unpolarized light through a polarizing filter, it comes out polarized in the direction corresponding to the filter orientation. Viewing this as a matter of acquiring information about the photons is certainly not complete. If you have three filters oriented at angle ##0^o##, ##45^o## and ##90^o##, 12.5% of the unpolarized photons (1/8 of them) will pass through all three filters. That can't possibly be a matter of just learning the pre-existing polarization of the photons, because it is impossible to have a photon that will pass through a filter at both 0 and 90 degrees. Passing through the filter changes the polarization of the photons. So it's not simply a matter of updating information.
I did not use the incorrect notion that there is a "pre-existing polarization of the photons" that stays the same throughout the life of the photon. This is physically inaccurate: the polarisation of a photon changes when it interacts with a polarising filter.
Instead what you have is the following situation. After a photon reaches a polarising filter it either passes through and acquires a specific definite state of polarisation or it does not pass through. The probability of it passing through is determined by its previous (possibly definite, possibly different) state of polarisation.
So when you have detected a photon that has passed through a set of polarising filters, you know the state of polarisation it had in the space between each two polarising filters. This polarisation changes at each filter if the filters are not aligned.
So no problem there.
 
  • #149
Elroch said:
I did not use the incorrect notion that there is a "pre-existing polarization of the photons" that stays the same throughout the life of the photon. This is physically inaccurate: the polarisation of a photon changes when it interacts with a polarising filter.
Instead what you have is the following situation. After a photon reaches a polarising filter it either passes through and acquires a specific definite state of polarisation or it does not pass through.

Okay, but "acquiring a definite state of polarization" is what is meant by "collapse". You were saying that it was about information. I don't see that it has anything to do with information.
 
  • #150
It's all about information. :) The information interpretation of quantum mechanics is entirely valid and I can detect no differences between it and my own way of thinking.
A wave function is a description of what is known about a particle which includes its position and momentum, but also all information about polarisation, spin etc., in full generality. (Also eg even flavor, in the case of neutrino oscillation).
In both the most common case of the discovery of the position of a particle by detection which is the typical example of "wave function collapse" and the case of a photon passing through a filter, what happens is an interaction between the particle and another quantum object which in the first case determines the position of the particle and in the second case determines its polarisation afterwards.
Position is an infinite dimensional property expressed in terms of a unique preferred basis of delta functions at every point, while polarisation is a 2-dimensional property which can be expressed equally well in terms of bases based on different chosen orientations: this is the distinct property that makes experiments with polarising filters different.
In both the case of position and polarisation, clearly the properties change as a wave function evolves. As I see it, the difference is that the former changes constantly, the latter changes only with certain interactions (hence astronomers can measure polarisation produced light years away).
 
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