Area bounded by Curves Integration Question

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SUMMARY

The discussion focuses on finding the area bounded by the curves defined by the equations x=(y-1)²-1 and x=(y-1)²+1, specifically from y=0 to y=2. Participants clarify that x is already expressed as a function of y, which allows for direct integration with respect to y without needing to manipulate the equations further. The confusion arises from interpreting the integration bounds, which should be from y=0 to y=2, rather than x-values. This understanding is crucial for correctly setting up the integral to find the desired area.

PREREQUISITES
  • Understanding of definite integrals in calculus
  • Familiarity with functions and their inverses
  • Knowledge of quadratic equations and their graphs
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the process of setting up definite integrals for area calculations
  • Learn about the properties of quadratic functions and their graphs
  • Explore the concept of changing variables in integration
  • Practice problems involving area between curves using different functions
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Students studying calculus, particularly those focusing on integration techniques and area calculations between curves.

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Homework Statement



Find the region bounded by the two functions from y=0 to y=2

equations given:
x=(y-1)2 -1
x=(y-1)2 +1

express x as a function of y and integrate it with respect to y

Homework Equations



equations given:
x=(y-1)2 -1
x=(y-1)2 +1


The Attempt at a Solution



Set x as a function of y

sqrt(x+1) + 1 =y
sqrt(x-1 ) + 1 = y

4. The confusion

The second equation doesn't actually exist until x =1...does that mean I have to just integrate from 1 to 2? But...

It says from y=0 to y=2... I am confused about this. I am told to express x as a function of y and integrate it with respect to y... I am unclear as to the meaning of this. It would make more sense if this was x=0 to x=2... please help!
 
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Okay, I think the two equations you have are:
##x=(y-1)^2-1##
##x=(y-1)^2+1##

Think about the wording: "express x as a function of y", this means that you aren't supposed to change the equations because x should be isolated, and it already is. Remember now that when you are integrating a function ##x=f(y)## that the bounds of integration will be from ##y=a## to ##y=b##, not X's.

So you don't have the manipulate the equations because x is already isolated, can you see where to go on from here?
 
Ahhh yes! Thank you! The wording confused me greatly; I think that was the problem. Thank you for your time.
 

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