Area perpendicular to a magnetic field from Faradays Law

AI Thread Summary
The discussion centers on the concept of "Area perpendicular to the magnetic field" in relation to Faraday's Law, specifically in the context of a permanent magnet. It questions whether this area is equivalent to the size of the permanent magnet or the area occupied by the stator wire in an axial flux generator. Participants clarify that the area can vary based on the specific calculations being performed. The voltage generated is linked to the rate of change of magnetic flux, not solely the area of the magnet or stator. Understanding the appropriate magnetic units and geometry is essential for accurate calculations.
jearls74
Messages
53
Reaction score
1
Hello Everyone,

I have a question concerning the "Area perpendicular to the magnetic field".

If the field was produced by a permanent magnet, would the "Area perpendicular to

the magnetic field" be the same size as the Area of the permanent magnet?
 
Engineering news on Phys.org
jearls74 said:
Hello Everyone,

I have a question concerning the "Area perpendicular to the magnetic field".

If the field was produced by a permanent magnet, would the "Area perpendicular to

the magnetic field" be the same size as the Area of the permanent magnet?

The area can be anything you want. It just depends on what you are trying to find. Can you provide more context to your question?
 
When calculating voltage for an axial flux generator with a permanent magnet rotor,

would the "Area perpendicular to the magnetic field" be the Area that the wire in the stator

occupies, or would the "Area perpendicular to the magnetic field" be the same size as the

Area of the permanent magnet? I believe the " Area perpendicular to the magnetic field" is

is Area of the permanent magnet that the field is coming from and not the Area of the stator

that the wire occupies but i need someone that knows more about Faradays Law to tell me

if I am right or not?
 
Check out this Faraday's Law explanation.

farlaw.gif
 
Nice job Don ! Great link, and scholarly...

The voltage is determined by the magnetic flux enclosed by your turns... Well,,, Actually by rate of change of that flux...
Probably there's several different ways to calculate that.

@ original poster:
Brush up on your magnetic units.
One weber per second will cause one volt in one turn whatever its area. You'll have to adapt that to whatever geometry and units you are given.


old jim
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Thread 'Weird near-field phenomenon I get in my EM simulation'
I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
Back
Top