whatdofisheat
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to take the area under a graph of
(1+2^x) from 0 to 30 how can you do this and what is the answer
(1+2^x) from 0 to 30 how can you do this and what is the answer
True indeed, but how does that apply here? 1+2x > 0 for all real x, so \int\limits_0^{30} {\left( {1 + 2x} \right)dx} is (represents) indeed, as asked by the OP, the area under the curve y=1+2x (additionally bounded by y=0, x=0, and x=30).quasar987 said:The term "area under the curve" can lead to confusion, because in the intervals where the function is negative, the integral actually gives the negative of the area not under but above the curve.
whatdofisheat said:to take the area under a graph of
(1+2^x) from 0 to 30 how can you do this and what is the answer
I don't have a "physically remove" button anywhere!HallsofIvy said:bomba923, when you delete a message do you have a "Physically remove" button below "Delete" and "Do Not Delete"? If so, clicking on that will not leave the "debris" behind that just using "Delete" does!