Ask about simulation using pspice

  • Thread starter Thread starter newbie92
  • Start date Start date
  • Tags Tags
    Pspice Simulation
AI Thread Summary
The discussion focuses on simulating a circuit using PSpice to generate a Bode Plot for an amplifier output across a load resistor (RL) from 10Hz to 10MHz. Participants confirm that the maximum gain and cut-off frequency can be derived from the Bode Plot. The key question raised is about identifying the frequency at unity gain, defined as the point where the output voltage equals the input voltage. Clarifications are provided that this occurs when the gain of the circuit drops to 1. The conversation highlights the importance of accurately interpreting the Bode Plot to extract these parameters.
newbie92
Messages
2
Reaction score
0

Homework Statement


Simulate the circuit from 10Hz to 10MHz.
Produce the Bode Plot for the amplifier output (across RL).
From the Bode plot, determine the following:
i) Maximum gain, A(max)
ii) The cut-off frequency, fc.
iii) The frequency at the unity gain.

2. The attempt at a solution
the maximum gain and cut-off frequency i obtained from the graph,but what is the mean by frequency at the unity gain?
 

Attachments

  • Capture.PNG
    Capture.PNG
    6.4 KB · Views: 526
  • Capture2.PNG
    Capture2.PNG
    3.8 KB · Views: 547
  • Capture3.jpg
    Capture3.jpg
    6.6 KB · Views: 527
Physics news on Phys.org
newbie92 said:

Homework Statement


Simulate the circuit from 10Hz to 10MHz.
Produce the Bode Plot for the amplifier output (across RL).
From the Bode plot, determine the following:
i) Maximum gain, A(max)
ii) The cut-off frequency, fc.
iii) The frequency at the unity gain.

2. The attempt at a solution
the maximum gain and cut-off frequency i obtained from the graph,but what is the mean by frequency at the unity gain?

That should be the frequency where Vout = vs. That is, where the gain of the circuit drops to 1.
 
then the answer is like the graph below?
when vout=vs=1v
 

Attachments

  • Capture.jpg
    Capture.jpg
    7.9 KB · Views: 488
newbie92 said:
then the answer is like the graph below?
when vout=vs=1v

I suppose that would be it (It's hard to make out the detailed contents of the image with its faint lines and lettering on a black background).
 
Back
Top