Ask, the resistance/phase of the load

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In a discussion about calculating the resistance and phase of a balanced 3-phase purely resistive load, the user presented equations for power calculations based on line voltage and current. They derived the phase angle (theta) using the difference in wattmeter readings, resulting in a value of 0.810 and a power factor of 0.999. The user questioned whether to calculate resistance using the formula R = V/I or the wattmeter results. Respondents clarified that the resistance can indeed be calculated directly from the voltage and current values. The conversation emphasizes understanding the relationship between resistance, phase angle, and power in electrical systems.
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Homework Statement



I was asked to calculate the value of the resistance/phase of the load in balanced 3-phase purely resistive load. it stated that there are two different ways to obtain the solution.

Homework Equations



W1 = VL IL cos (30-theta)
W2 = VL IL cos (30+theta)

where Voltage Line = 110, Line current = 0.86, W1=77 and W2=76.5

The Attempt at a Solution



W1+W2=153.5

theta=tan-1 (\sqrt{3} * (W1-W2)/(W1+W2))

thus, I obtained theta = 0.810 where cos theta (pf) = 0.999

from this, how I calculated the resistance? is it only R=V/I = 110/0.86 = 127.91? or using the wattmeter result?
 
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help..anyone?
 
There are a few things I don't understand about your question... But, I will be direct, first.

You know that R = V/I. Also, you have figured out what the resistance is and what the phase is. So what's your problem?
 

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