Assume that x is a positive multiple of 5 and is greater than 5.

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The problem states that x is a positive multiple of 5 and greater than 5, with the inequality 2x + 1 < 100. The manipulation of the inequality leads to x being less than 49.5, suggesting potential values for x as multiples of 5. However, the provided solution indicates that x must also be a multiple of 2.5, resulting in 20 total multiples from 2.5 to 50. After eliminating the inappropriate values, the correct answer is determined to be 17 possible values for x, highlighting a misinterpretation of the original problem statement.
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Homework Statement



Assume that x is a positive multiple of 5 and is greater than 5. If 2x + 1 < 100, how many values for x are possible?

Homework Equations





The Attempt at a Solution




How I solved the problem

First manipulated inequality:

2x+1<100
=>
2x < 99
=>
x < 49.5


Now, x is a multiple of 5 => x = 5k for some integer k > 1 (because we are given that x > 5)

x < 49.5 => 5k < 49.5 => k < 9.9

So the possible values of k (since k is an integer > 1):
2, 3, 4, 5, 6, 7, 8, 9

So there are 6 values, namely: 5(2), 5(3), 5(4), 5(6), 5(7), 5(8), 5(9) - 10, 15, 20, 25, 30, 35, 40, 45




Solution they have given:


The correct answer is 17. (To gain credit for answering the question correctly you must type the number 17 in the numeric-entry box.) Given that 2x is a multiple of 5, x must be a multiple of 2.5. The total number of such multiples from 2.5 to 50 is 20. Given that x is greater than 5 and that 2x + 1 < 100, you must eliminate 2.5, 5.0, and 50 from the list of 20 multiples, which leaves 17 possible values for x.


I am very confused by the solution they have given and have no idea what aspect of this problem I am interpreting incorrectly
 
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fleazo said:

Homework Statement



Assume that x is a positive multiple of 5 and is greater than 5. If 2x + 1 < 100, how many values for x are possible?





Solution they have given:


The correct answer is 17. (To gain credit for answering the question correctly you must type the number 17 in the numeric-entry box.) Given that 2x is a multiple of 5, x must be a multiple of 2.5. The total number of such multiples from 2.5 to 50 is 20. Given that x is greater than 5 and that 2x + 1 < 100, you must eliminate 2.5, 5.0, and 50 from the list of 20 multiples, which leaves 17 possible values for x.


I am very confused by the solution they have given and have no idea what aspect of this problem I am interpreting incorrectly

This seems to be the problem.
 
hi fleazo! :smile:
fleazo said:
Assume that x is a positive multiple of 5 and is greater than 5. If 2x + 1 < 100, how many values for x are possible?

Given that 2x is a multiple of 5, x must be a multiple of 2.5.

clearly, there's a misprint, and the question should start "Assume that 2x is a positive multiple of 5" :wink:
 
oh ok, thank you guys so much, I guess I should have seen that, I was just looking at it thinking, what the hell am I doing wrong
 
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