Solving Asymptote Trouble on Scatter Plot: Regression or Line Fit?

  • Thread starter Thread starter CestLaVie9009
  • Start date Start date
  • Tags Tags
    Asymptote
AI Thread Summary
The discussion focuses on fitting a scatter plot with an appropriate regression or line. A suggested equation, y=3/((x-3.75)/2.75)+9, is noted as a good fit. To eliminate the unwanted curve left of the asymptote, adjusting the minimum x-value to x_low = 3 is recommended. Additionally, improving the fit can be achieved using Excel with the Solver add-in. Overall, participants emphasize the importance of adjusting the x-range and refining the equation for better results.
CestLaVie9009
Messages
1
Reaction score
0
scatter plot needs a regression? or line best fitting it.

so far y=3/((x-3.75)/2.75)+9 is a pretty good fit

graph is attached

any suggestions on how to get rid of everything left of the asymptote?
 

Attachments

Physics news on Phys.org
Hello, I do not know how your calculator works. But if you set the minimum value of x so that the bottom left curve won't be displayed, it should work. Or are you looking for another equation to fit your data?
 
A few comments:

The 3 and 2.75 in your equation can be combined into a single number.

As kazumi said, changing the range of x-values should get rid of the unwanted curve. Looks like x_low = 3 should work here.

If you're looking to improve the fit, it can be done in Excel. You would need to have the Solver add-in installed.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top