At what distance from a carbon nucleus is the electric potential 2.1 V?

AI Thread Summary
To determine the distance from a carbon nucleus where the electric potential is 2.1 V, the relevant formula is V = KQ/r, where K is Coulomb's constant and Q is the total charge of the carbon atom. Carbon has 6 electrons, so the total charge Q is 6 times the charge of an electron. The user is uncertain about using the correct formula, initially considering V = KQ/r^2, which is applicable for electric fields rather than potential. The correct approach involves rearranging the formula to solve for r. The discussion emphasizes the importance of using the right equation for calculating electric potential.
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Homework Statement



At what distance from a carbon nucleus is the electric potential 2.1 V? Carbon atoms have 6 electrons in the atomic shell.

Homework Equations



v= K Q / r^2 OR K Q / r (NOT SURE)

The Attempt at a Solution



use voltage potential for point charge

Using either v= K Q / r^2 OR K Q / r (not sure)

V given, Q ( 6* electron charge) , solve for r
 
Last edited:
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It's the forumula with "r" in the denominator. The "r^2" forumula is for the electric field.
 

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