Garvit Goel said:
thanks Mr. Forte.
But what my problem is that the electrones spin around the nucleus. And when these electornes spin these probability clouds around the nucleus must also spin?
1. Electrons do not spin around the nucleus.
2. Electrons have orbital angular momentum, which is similar to the angular momentum that would be associated with a particle in a classical orbit. Of course, this is not the correct physical picture, since electrons are quantum particles. Therefore, one of the quantum numbers associated with electrons in atoms (the l quantum number), specifies the orbital angular momentum of the state.
3. The projection of the orbital angular momentum on a axis of quantization (usually the z-axis by convention), is also a conserved quantity in single-electron atoms, and thus we associate a quantum number with it as well (m
l). The value of this quantum number tells us the spatial orientation of the orbital with respect to the axis of quantization.
4. Electrons have spin angular momentum, which is intrinsic angular momentum that we know they must possesses in order to account for their observed behavior (i.e. the Pauli exclusion principle). One of the quantum numbers for an electron in an atom (m
s), tell us the projection of that angular momentum on the axis of quantization (usually the z-axis).
The point that has the most relevance to your question (I think) is number 3. The values of l and m
l tell you the shape and orientation of the orbital with respect to the axis of quantization. In isotropic space, the choice of axis is arbitrary, but if there is an anisotropic potential present (e.g. a magnetic field in the labrotory fixed frame), then that becomes the most logical choice for the quantization axis. This provides the basis for the Zeeman splitting of the m
l levels by a magnetic field.