Automobile Deceleration Problem

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SUMMARY

The discussion centers on calculating the time and distance required for an automobile to stop when decelerating at 6.00 m/s² from an initial speed of 27.0 m/s. To determine the stopping time, the formula t = v/a is applied, resulting in 4.5 seconds. The distance traveled during deceleration is calculated using the formula s = 0.5 * a * t², yielding a distance of 60.75 meters. These calculations demonstrate the straightforward application of kinematic equations in physics.

PREREQUISITES
  • Understanding of kinematic equations
  • Familiarity with concepts of acceleration and deceleration
  • Basic algebra for solving equations
  • Knowledge of units of measurement in physics
NEXT STEPS
  • Study the derivation and application of kinematic equations
  • Learn about the effects of different deceleration rates on stopping distances
  • Explore real-world applications of deceleration in automotive safety systems
  • Investigate the impact of initial speed on stopping time and distance
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding vehicle dynamics and stopping distances.

mr1214
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Hey! I have this question that I can't find the answer to anywhere!

The Brakes of an automobile can decelerate at 6.00 m/s2. a) How many seconds are required to stop the automobile if it is traveling at a rate of 27.0 m/s? b) How many meters does the automobile travel during this deceleration? :frown: Can you help me please...I'm lost!
 
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A deceleration of 6m/2^2 means that every second the velocity decreases by 6m/s. When something travels at 27m/2 I hope you can figure out after how many seconds the velocity is zero...

For the amount of metres traveled you can use following formula for constant acceleration a for a time t

s=\frac{1}{2}at^2
 
what is the thing that you are not getting through, because the question is very easy and you just have to apply formulae. you will get separate help if you think you need clarity in a concept. but for that you will have to express yourself
 

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