Average acceleration and average force

AI Thread Summary
The discussion focuses on calculating the average acceleration and force exerted on a steel ball with a mass of 17 grams, launched at 6 m/s and stopping over 1 mm. The initial calculation for acceleration yielded -18 m/s², but further checks revealed it should be -1800 m/s², highlighting the significant deceleration required. Participants noted that such a rapid stop over a short distance necessitates a large force, emphasizing the physics behind the scenario. The calculations prompted discussions about the arithmetic involved and the implications of the high acceleration value. Stopping a fast-moving object in a minimal distance results in substantial forces, which is a critical point in understanding the dynamics at play.
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Homework Statement


Steel ball with a mass 17 grams, is launched at a speed of 6 m/s, into someones eye. The ball comes to a rest over a distance of 1mm.

A) What is the average acceleration experienced by the ball to stop it?

B) What is the deaccelerating force that must be exerted on the ball (by the eyeball), and thus, what is the average force on the eyeball?


Homework Equations





The Attempt at a Solution



I tried using the Vf^2 - Vi^2 = 2a*d (where d is displacement, vf is final veloctiy, vi is initial velocity and a is acceleration) but came out with -18m/s^2 for the acceleration. I don't think that is right however



Any help is greatly appreciated
 
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Check your arithmetic.
 
I stuffed up the arithmetic.
Answer should be -1800. Is that right? Seems big for acceleration.
 
Check the numbers, I get an even bigger acceleration. Anyway yes, it is big for an acceleration, but also from 6 m/s (21.6 Km/h) to rest in only 1 mm is really a lot... to stop something that fast in such short distance will require (of course depending on mass) a huge force, at least for usual objects (therefore not too light).
 
tooperoo said:
I stuffed up the arithmetic.
Answer should be -1800. Is that right? Seems big for acceleration.
You're still off by a factor of 10, so recheck that math. Yes, it's big. But 1 mm is a small distance to come to rest in.
 
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