To calculate the average acceleration of a bird flying north at 5 m/s and then veering east at the same speed over a 2-second interval, vector subtraction is used. The initial velocity (V1) is north, and the final velocity (V2) is east, making them perpendicular. The change in velocity is found using the Pythagorean theorem, resulting in a magnitude of approximately 7.07 m/s. Dividing this by the time interval of 2 seconds gives an average acceleration of about 3.54 m/s². The final answer confirms the calculation of average acceleration.