(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ball falls on the surface from 10m height and rebounds to 2.5m.If duration of contact with floor is 0.01 sec,then average acceleration during contact is-

g = 10m/s^2

2. Relevant equations

[tex]

\alpha = \frac{v_2 + v_1}{t}

[/tex]

3. The attempt at a solution

Now here

[tex]

v_{1} = \sqrt{2gh_{1}

[/tex]

[tex]

v_{1} = \sqrt{50}

[/tex]

and

[tex]

v_{2} = \sqrt{2gh_{2}

[/tex]

[tex]

v_{2} = \sqrt{200}

[/tex]

[tex]

\alpha = \frac{\sqrt{200+50}}{0.01}

[/tex]

After solving all of this,I get the answer the answer as 1581.14 m/s^2,but the answer in the book is 2100 m/s^2.Am i doing anything wrong over here?

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# Homework Help: Average acceleration of a falling ball on contact with floor

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