Average acceleration race horse problem

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Homework Help Overview

The problem involves calculating the average acceleration of a racehorse, Secretariat, based on its performance in the Kentucky Derby, where the times for each quarter mile are provided. The context includes the need to consider average speed and acceleration over the entire race.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of average speed for the final quarter mile and how it relates to average acceleration. There are questions about the interpretation of the problem, particularly regarding whether to use total time or individual segment times for calculations.

Discussion Status

Some participants have provided insights into unit conversions and the implications of using different time frames for calculating acceleration. There is an ongoing exploration of the problem's wording and its impact on the calculations, with no clear consensus reached yet.

Contextual Notes

Participants note potential confusion arising from the problem's wording and the necessity to clarify whether to consider the horse's initial speed as zero or to use the average speed over the entire race for acceleration calculations.

galuda
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Homework Statement


Secretariat ran the Kentucky derby with time for the quarter mile of 25.2s, 24s, 23.8s, and 23s. Assuming that secretariat's instantaneous speed at the finish line was the same as the average speed during the final quarter mile, find his average acceleration for the entire race.



Homework Equations



average velocity=distance/time
acceleration=change in velocity/time



The Attempt at a Solution

Got the first part of this problem right which was just what was his average speed during the first quarter mile in ft/s. That was just 1320ft/25.2. Now the way i read this part of the question was using his average velocity for the final quarter mile which would be 1320/23 = 57.3913ft/s find his average acceleration for the entire race which would then be 57.3913/average time for all 4 1/4mile runs. However the answer i get of 2.391m/s^2 is not the right answer. Can anyone tell me how I am reading this question wrong?
 
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57.3913 \div 24 \neq 2.391 METRES S^{-2}.

Rather it is equal to 57.3913 FEET S^{-2}.

What you want to do then is convert into metres per second squared
(I would usually stick to metres from the very start... 1609 metres per mile)

I'm assuming the method is right, for the horse accelerating from speed 0 to the
final speed.
 
Sorry i mean it is equal to 2.391 FEET ^{-2}
 
Sorry i mean it is equal to 2.391 FEET ^{-2}.

I'm just wondering also whether you might want to divide by the sum of the times if you were looking at it in the sense that he starts at speed 0 and gets to a speed 57.3913 (as he does this over the entirity of the race, and i assume that's what's meant by average acceleration)
 
Well they want the answer in ft/s^2 which is why I didn't convert to meters, but I've also tried it using your last posted method prior to asking for help and that doesn't work either. I think the question is just worded poorly, because I've tried it every way I can think of trying to make the words work, but it just doesn't work.

Thanks though.
 

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