Average Velocity over intervals

AI Thread Summary
To find the average velocity of an arrow shot upwards at 50 m/s, the height function is given by h=50t-0.36t^2. The average velocity over the interval [1, 1.03] can be calculated using the formula for average rate of change, which involves evaluating the height at both endpoints and finding the difference. Specifically, this involves computing h(1) and h(1.03) to determine the average rate of change over the specified interval. The discussion confirms that this is a secant problem rather than calculating the average value of the function. The final average velocity result should be expressed to four decimal places.
step1536
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An arrow is shoot up in the air at 50m/s. Its height in meters after t sec. is h=50t-0.36t^2. Find the average velocity over interval [1,1.03], four decimal places.
 
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step1536 said:

Homework Equations


this may help (if I remember it correctly)

F(x)_{average}=\frac{1}{b-a} \int_{a} ^{b} f(x) dx
 
I think this is a simple secant problem where you find the average rate of change between the two points (1, h(1)) and (1.03, h(1.03)) and not the average value of the function.
 
Thanks alot. I knew that but I wanted to make sure.
 
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