Avg force on projectile shot from cannon?

AI Thread Summary
To calculate the average force on a projectile fired from a cannon, one must consider the change in kinetic energy. Given a barrel length of 6.8 m and a projectile mass of 1.2 kg with a muzzle velocity of 88.3 m/s, the average force can be determined using the formula F = ΔKE / d. The calculated average force is approximately 687.96 N. This approach effectively combines the principles of physics to derive the necessary force acting on the projectile.
IDKPhysics101
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A cannon has a barrel 6.8 m long and fires a 1.2 kg projectile with a muzzle velocity of 88.3 m/s. What is the average force (in N) on the projectile?
 
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IDKPhysics101 said:
A cannon has a barrel 6.8 m long and fires a 1.2 kg projectile with a muzzle velocity of 88.3 m/s. What is the average force (in N) on the projectile?

You need to show some attempt before anyone at PF can help you.

Start by considering change in kinetic energy of the projectile.
 
F=687.96n
 
Yes that is correct.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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