Balancing a cylinder on an incline with a mag. field

AI Thread Summary
To balance the cylinder on the incline, the current in the coil must create a torque that counteracts the gravitational torque acting on the cylinder. The gravitational force parallel to the ramp is calculated as F = mgsin(theta), where m is the mass of the cylinder. The magnetic force on the current-carrying wire is given by F = IlB, and the torque produced by this force is Torque = IlBR. The key is to equate the torques from the magnetic field and gravity to find the required current for equilibrium. Further clarification on the angle theta and the direction of forces may be needed to finalize the solution.
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Homework Statement


A cylinder with radius R, length l, and density ro has a 10 turn coil of wire wrapped lengthwise. The cylinder is placed on the ramp tilted at an angle theta, with edge of the coil parallel to the ramp's slope. A uniform mag. field points straight up.

For what loop current will the cylinder rest on the ramp. Assume static friction is large enough to keep the cylinder from sliding down the ramp.


Homework Equations





The Attempt at a Solution



So, here are my thoughts. I need to find the current such that the torques exerted by the magnetic field on the wires balance the torque exerted by the force of gravity

on a slope F = mgsin(theta), = ro*pi*R^2 * l, so the force of gravity is parallel to slope of the ramp, I think.

Then for a current-carrying wire F = IlBsin(theta) Is theta = 90?

F = IlB Torque = IlBR

I'm not sure what to do at this point because I think that the forces exerted on the two wires by the magnetic field are equal and in opposite directions. I haven't done dynamics for awhile, so I could use a push in the right direction.

Thanks
 
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