Balancing four point charges so that the net force acting on each charge is 0.

haldavidc
Messages
1
Reaction score
0

Homework Statement



Find positions of four charges in a plane (+1C, -1C, +2C, -2C) that result in an equilibrium (zero net force on each charge). Report positions as four (x,y) pairs.

Homework Equations



F = \frac{k_{e}q_{1}q_{2}}{r^{2}}

The Attempt at a Solution



I had no idea where to start. It seemed to me that regardless of where I put the charges there would be a net force.
 
Physics news on Phys.org
In your equation of the force between two charges, when does the force tend toward zero?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top