Ball dropped from heigh and bounces to height, change in momentum?

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A bouncy ball with a mass of 85.3 grams is dropped from a height of 13.17 meters and rebounds to a height of 5.12 meters. To find the change in momentum, the initial and final velocities at impact and rebound need to be calculated using kinematic equations. The equation V^2 = Vo^2 + 2a(X - Xo) is suggested for determining the velocity at the moment of impact, with initial height as Xo and the ground as X. The calculated velocity at impact is approximately 1.34 m/s, which is necessary for determining the change in momentum. The discussion emphasizes the application of conservation of energy principles to solve the problem.
IDKPhysics101
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A bouncy ball of mass 85.3 grams is dropped from a height of 13.17 meters. It rebound to a height of 5.12 meters. What was the change in momentum (in kgm/s) of the bouncy ball?
 
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IDKPhysics101 said:
A bouncy ball of mass 85.3 grams is dropped from a height of 13.17 meters. It rebound to a height of 5.12 meters. What was the change in momentum (in kgm/s) of the bouncy ball?

What attempt did you try?

How would you find the speed of the ball at the point where it hits the ground?

(Hint: Think of conservation of energy)
 
i was thinking one of the kinematic equations but not sure how to find initial and final velocity or what to set each one to to find the other
 
IDKPhysics101 said:
i was thinking one of the kinematic equations but not sure how to find initial and final velocity or what to set each one to to find the other

Well take from the start to when it hits the ground, using a kinematic equation relating height and velocity, what is the velocity as it hits the ground?
 
V^2=Vo^2+2a(X-Xo)?

would 13.17 be Xo and 5.12 be X?

would the Vo be 0?

would the velocity when it hits the ground be 1.34m/s?
 
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