Ball on a string (vertical circle)

Click For Summary
SUMMARY

The discussion revolves around calculating the tension in a string when a 500 g ball moves in a vertical circle with a radius of 1.01 m. At the top of the circle, the speed is 4.3 m/s, resulting in a calculated tension of 9.15 N, while at the bottom, with a speed of 7.62 m/s, the calculated tension is 28.7 N. However, these values are incorrect as they do not account for gravitational forces acting on the ball. To accurately determine the tension, one must incorporate the gravitational force and utilize a force diagram for clarity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of circular motion dynamics
  • Familiarity with gravitational force calculations
  • Ability to draw and interpret free-body diagrams
NEXT STEPS
  • Review the concept of centripetal force in circular motion
  • Learn how to calculate gravitational force acting on an object
  • Study the principles of tension in strings under varying forces
  • Practice drawing free-body diagrams for objects in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to tension and forces in vertical circular motion.

redlightgreen
Messages
3
Reaction score
0

Homework Statement


a 500 g ball moves in a vertical circle on a 1.01 m long string. if the speed at the top is 4.3 m/s, then the speed at the bottom will be 7.62 m/s. what is the tension of the string when the ball is at the top? when is the tension of the string when the ball is at the bottom?


Homework Equations


tension = (Fnet)=mv2/r


The Attempt at a Solution


top:
tension = (Fnet)=(0.5 kg)(4.3)2/(1.01) = 9.15 N

bottom:
tension = (Fnet)=(0.5 kg)(7.62)2/(1.01) = 28.7 N

these answers are wrong, however. and I'm not exactly sure why.
pointers in the right direction would be much appreciated!
 
Physics news on Phys.org
The numbers you found were the magnitudes of the force pointing directly outward from the string, but that is not the tension in the string. Use the gravitational force on the ball to solve for the tension in the trope. Drawing a force diagram will make this problem more understandable.
 
@Engineering_PHY123 - this thread was started more than 11 years ago. The OP has not visited PF for more than 10 years.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 29 ·
Replies
29
Views
2K
Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
5K