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**[solved]Ballistic pendulum**

## Homework Statement

A bullet of mass m = 0.024 kg is fired with a speed of vi = 97.00 m/s and hits a block of mass M = 2.61 kg supported by two massless strings. The bullet emerges from the right side of the block with a speed of vf = 48.50 m/s. Find the height to which the block rises.

m1= 0.024 kg

m2= 2.61 kg

vi = 97 m/s

vf = 48.5 m/s

h = unknown

## Homework Equations

Before+JA collision

m1v1+ m2V2 = P

Ki = 1/2m1v1^2+1/2m2vf^2

1/2mv^2= mgh

## The Attempt at a Solution

I know i need to use con of momentum before and just after bullet contact to find v. But thats where im having problems at, im not really sure how to set it up to find v

I had been doing 1/2m1v1^2+1/2m2vf^2 = 3182.6 then trying to set that = mgh but it gives me 120.

If i can find that v i know id need 1/2*m2*V = m2*g*h

then solve from h there if im correct if someone could give me nudge into right direction would be great

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