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Banking corners Problem regarding assignment

  1. Aug 13, 2005 #1
    hey guys im having trouble with a banking problem i keep getting a sin theta value of 2 therefore i cant find the angle required, any ideas where im going wrong, below is a copy of my formulas
    Fnet = (MV^2) / R

    Fnet = (1000*16.67^2) / 10

    Fnet = 27788.89 N

    Fc = Mac

    Ac = V^2 / R

    Ac = 16.67^2 / 10

    Ac = 27.78889 ms ^ -2


    Fc = Mac

    Fc = 1000 * 27.78889

    Fc = 27788.89 N

    G sin Ө = v^2 / R

    9.8 sin Ө = 16.67^2 / 10

    9.8 sin Ө = 27.78889

    sin Ө = 27.78889 / 9.8

    sin Ө = 2.836
  2. jcsd
  3. Aug 13, 2005 #2


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    Have you gone through the text? I think your concept is not cleare. How you have written
    G sin Ө = v^2 / R
  4. Aug 13, 2005 #3
    im not sure what you mean, however the squares used to be a theta symbol if thats what you mean they just didnt convert into the forum.
  5. Aug 13, 2005 #4
    what is the question and maybe we can help you better
  6. Aug 13, 2005 #5
    i need to work out how banking a corner can help to increase road safety, using circular motion, friction etc... i have a car travelling at 60 km/h with a mass of 1000kg, the speed is allowed to vary but the mass must stay the same...
  7. Aug 13, 2005 #6


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    In this case the ideal situation is such that the sideway friction force is zero.
    The component of normal reaction will provide the necessary centripetal force.
    Resolve normal reaction in horizontal and vertical direction.
  8. Aug 13, 2005 #7
    how would i work out theta in this case?
  9. Aug 13, 2005 #8


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    Draw a diagram and indicate the forces you will find

    N cosq = mg (q is for theeta)
    N sinq = mv^2/R
    gives tanq = V^2/gR
  10. Aug 14, 2005 #9
    what does the character N stand for?
  11. Aug 15, 2005 #10


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    N stands for the normal reaction of the road which is normal to the roas and makes and angle 90 - q degree with the horisontal and q with upward vertical.

    Sorry for late, I was out of station.
    Last edited: Aug 15, 2005
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