Barometric formula and height ratios

AI Thread Summary
The discussion focuses on deriving the pressure ratio between two heights in an isothermal atmosphere using the barometric formula. The ratio of pressures, P(z2)/P(z1), can be expressed as e^(-(z2-z1)/y), where y is the scale height. Participants discuss the process of substituting P(z1) and P(z2) into the barometric formula and dividing them to simplify the expression. There is a clarification on using properties of exponents to divide exponential terms. The conversation highlights the importance of understanding algebraic manipulation in solving the problem.
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Homework Statement


Starting from the barometric formula for a thin, isothermal atmosphere, show that the ratio of the pressure P(z2) at height z2 to the pressure P(z1) at height z1 is given by

P(z2)/P(z1) = e(-(z2-z1)/y) where y is the scale height

Homework Equations


Barometric formula: P(z) =P(0) e(-z/y)

The Attempt at a Solution


looks easy but i just can see how?
 
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If it looks easy, then you should be able to see how.
Have you tried writing P(z1) and P(z2) in the barometric formula and just dividing them?

aside: on notation:

P(z)=P(0).exp(-z/y) ... in plain text, or, in LaTeX (worth learning)
P(z)=P_0 e^{-z/y}
 
Last edited:
I'm afraid my algebra is a little rusty, how do you divide e(-z2/y) by e(-z1/y)?
 
property of powers
x^a x^b = x^{a+b}... it's the same for the exponential function.
 
got it... just clicked
 
:) I get blind spots like that sometimes.
 
Yeah, thanks for the memory jog :-)
 

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