- #1
askor
- 169
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Member warned that homework problems must be posted in the Homework sections
How to solve these two absolute value problems?
1.
##|3x - 5| > |x + 2|##
My attempt:
From what I read in my textbook, the closest properties of absolute value is the one that uses "equal" sign
##|3x - 5| = |x + 2|##
##3x - 5 = x + 2##
##3x -x = 5 + 2##
##2x = 7##
##x = \frac{7}{2}##
##|3x - 5| = |x + 2|##
##3x - 5 = -(x + 2)##
##3x - 5 = -x - 2##
##3x + x = 5 - 2##
##4x = 3##
##x = \frac{3}{4}##
However, this absolute uses ">" sign. So, how do you solve this one?
2.
|x - 3| + |2x - 8| = 5
I don't understand at all of absolute value problem like above one. Please help me.
Note: this is the absolute value properties from my textbook (please see attached file).
1.
##|3x - 5| > |x + 2|##
My attempt:
From what I read in my textbook, the closest properties of absolute value is the one that uses "equal" sign
##|3x - 5| = |x + 2|##
##3x - 5 = x + 2##
##3x -x = 5 + 2##
##2x = 7##
##x = \frac{7}{2}##
##|3x - 5| = |x + 2|##
##3x - 5 = -(x + 2)##
##3x - 5 = -x - 2##
##3x + x = 5 - 2##
##4x = 3##
##x = \frac{3}{4}##
However, this absolute uses ">" sign. So, how do you solve this one?
2.
|x - 3| + |2x - 8| = 5
I don't understand at all of absolute value problem like above one. Please help me.
Note: this is the absolute value properties from my textbook (please see attached file).