Basic Electric Circuit: Find v1 & v2

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SUMMARY

The discussion focuses on solving a basic electric circuit to find the voltages v1 and v2. Using Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL), the user derived the equations v1 = 30 - 8i and established relationships between the currents in the circuit. The final values obtained are v1 = 14V and v2 = 6V, confirming the correctness of the calculations. The discussion emphasizes the importance of understanding potential dividers and the behavior of current sources in circuit analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with Kirchhoff's Current Law (KCL)
  • Knowledge of potential dividers in electrical circuits
  • Basic concepts of resistors in series and parallel
NEXT STEPS
  • Study advanced circuit analysis techniques using Thevenin's and Norton's theorems
  • Learn about the impact of current sources on circuit behavior
  • Explore the application of mesh and nodal analysis in complex circuits
  • Investigate the use of simulation tools like LTspice for circuit verification
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in mastering basic circuit analysis and voltage calculations.

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Homework Statement


Consider the circuit shown. Find the values of v1 and v2.

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Homework Equations

The Attempt at a Solution


I tried using KVL on the left closed loop and got:
$$v_{1} = 30 - 8i$$
I then used the current law between the two loops to get:
$$ i_{1} - v_{1} / 7 = v_{2} / 2 - 3$$
That's where I'm stuck. Do the two resistors next to a and b have any current flowing through them? Would it also be possible to treat the 3A current source as a resistor and combine it with the ##2\Omega## resistor it's in parallel with? Thanks.
 
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Perhaps try another approach. Are you familiar with the concept of a potential divider ?

If not then note that the current through the 3Ohm is zero and apply KCL to the node on the left of the 3Ohm. What does it tell you about the current through the 8 and 7 Ohm?

The current through the 4 Ohm is also zero.
 
Would it also be possible to treat the 3A current source as a resistor and combine it with the 2Ω 2\Omega resistor it's in parallel with?

Note the current through the 4Ohm is zero. Apply KCL to the node on the right of the 4Ohm. What does that say about the current through the 2 OHM?
 
CWatters said:
Perhaps try another approach. Are you familiar with the concept of a potential divider ?

If not then note that the current through the 3Ohm is zero and apply KCL to the node on the left of the 3Ohm. What does it tell you about the current through the 8 and 7 Ohm?

The current through the 4 Ohm is also zero.
So the current for both the 8 ohm and 7 ohm resistor would be ##i_{1}## and the current through the 2 ohm resistor would be 3 A. I can see how to solve it now. I'm getting v1 = 14 and v2 = 6, which looks correct.

Thanks for the help.
 
Yes v1=14V and V2 =6V is correct.
 

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