Basic Nuclear Fusion question on Binding energy

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Nuclear fusion involves combining two low-binding energy nuclei, such as deuterium, to form a nucleus with higher binding energy, like helium-4. The confusion arises from the relationship between binding energy and mass; a higher binding energy indicates a more stable nucleus with a lower mass per nucleon. This is because the energy released during fusion corresponds to a decrease in mass, as described by Einstein's equation E=mc². The negative binding energy signifies that the resulting nucleus is in a lower energy state, allowing energy to be released during the fusion process. Understanding these concepts clarifies why fusion can be an energy-releasing reaction.
JonDawe
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Hey guys, I'm getting a bit confused about nuclear fusion. I understand the basics of binding energy being the energy required to split the nucleons apart etc. and the fact that in nuclear fusion you are combining two particles e.g. (2 deuterium nuclei) with a lowish binding energy to form a particle (he-4 or something) with a higher binding energy. I'm just getting a bit confused at why a higher binding energy means that the mass of the particle relative to the masses of the 2 fusion reactants is lower? Can someone here help explain it?

I know nuclei with higher binding energy per nucleon have a lower*atomic weight*per nucleon, but I'm kind of confused at why?
 
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Binding energy is always negative (otherwise the state is not bound), and "high" is usually meant as absolute value. So helium has a "high negative" binding energy, it is actually a low-energetic state. This means that fusion can release energy while forming this state.
 
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