- #1
Moogie
- 168
- 1
Hi
Given this limit
[tex]\lim_{h \to 0} \frac{1-cos(h)}{h} = 0[/tex]
can you rearrange
[tex](sin(x) (\frac{cos(h)-1}{h}))[/tex]
to
[tex](sin(x) \cdot -1 \cdot (\frac{1-cos(h)}{h}))[/tex]
so that when you take the limit as h goes to 0 you get: sin(x) x -1 x 0 = 0
thanks
Given this limit
[tex]\lim_{h \to 0} \frac{1-cos(h)}{h} = 0[/tex]
can you rearrange
[tex](sin(x) (\frac{cos(h)-1}{h}))[/tex]
to
[tex](sin(x) \cdot -1 \cdot (\frac{1-cos(h)}{h}))[/tex]
so that when you take the limit as h goes to 0 you get: sin(x) x -1 x 0 = 0
thanks