Basis of range of a matrix relative to some bases

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SUMMARY

The discussion centers on finding a basis for the range of a linear transformation T from R5 to R3, represented by the matrix A. The matrix A, relative to specific bases of R5 and R3, yields a basis for the range as [(4/3, 1, 1), (1/3, 1, 0)]. The confusion arises from the difference in bases used for representation, emphasizing that while the vectors may differ, they must maintain the same span. The transformation requires converting representations between the specified bases and the natural basis.

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Homework Statement


Let T be the linear transformation of R5 into R3 that has the matrix

A =
1 3 2 0 -1
2 6 4 6 4
1 3 2 2 1

relative to the bases [(1,1,1,1,1), (1,1,1,1,0), (1,1,0,0,0), (1,0,0,0,0), (0,0,0,0,1)] of R5 and [(1,1,1), (0,1,0), (1,0,0)] of R3. Find a basis for the range of T.


Homework Equations





The Attempt at a Solution



The whole ordeal with the different bases for R5 and R3 confuses me. If this was just an ordinary matrix, I'd have row reduced and gotten my basis for the range to be
{[1 2 1]^T and [0 6 2]^T.

But this isn't the correct answer. The correct answer is

[(4/3, 1, 1), (1/3, 1, 0)].


Any suggestions? Much thanks.
 
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The vectors you found are representations relative to the basis {(1,1,1), (0,1,0), (1,0,0)}. The answer you gave is relative to the natural basis. You just need to change representations from one basis to the other. Keep in mind that a basis is not unique, so you may come up with two vectors that don't match the answer, but they just need to have the same span.
 
vela said:
The vectors you found are representations relative to the basis {(1,1,1), (0,1,0), (1,0,0)}. The answer you gave is relative to the natural basis. You just need to change representations from one basis to the other. Keep in mind that a basis is not unique, so you may come up with two vectors that don't match the answer, but they just need to have the same span.

Hi, thank you very much for your answer.
 

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