Batter hits a ball momentum problem

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The discussion revolves around calculating the impulse delivered to a baseball by a bat and determining the baseball's velocity after impact. The force exerted by the bat is given as F(t)=(13000N)sin(1.05ms^-1) over a duration of 3.00ms, leading to an impulse of 24.8N. Participants debate the nature of the collision, with suggestions that it may be elastic, while clarifying that impulse represents a change in momentum. There is confusion regarding the use of the sine function in the force equation, as it typically relates to angles rather than linear motion. The final calculated velocity of the baseball after leaving the bat is 47.5m/s.
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A batter hits a ball with a force of F(t)=(13000N)sin(1.05ms^-1) for 3.00ms. A baseball is thrown so it has a velocity of 35.0m/s toward the batter just before it hits the bat. Assuming the baseball has a mass of 300.0g calculate:

a. the impulse delivered to the ball over the 3.00ms

b.the velocity of the baseball just after it leaves the bat

I really don't know where to start. The answers are impulse=24.8N and 47.5m/s

Any help would be great!
 
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I'd start with the equations, and identifying what type of collision it is. Would you call this collision elastic, inelastic, or perfectly inelastic?
 


i would say its elastic, what equations are you talking about?
 


F(t)=(13000N)sin(1.05ms^-1)

i don't understand. sin is a function for angles, how can you deduce "sin 1.05ms-1"

impulse=24.8N

impulse is basically change in momentum. so the unit is kg ms-1 not N
 


m1v1=m2v2

impulse=F*change in time
 
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