- #1
nophun6
- 26
- 0
Hello.
Here is my question: Is it possible to connect 2 identical batteries to make 2 bulbs connected in series light just as brightly as one bulb connected to one battery?
Reasoning: let's say each battery has a voltage of 1.5V and that each light bulb is equal and has a resistance of 4 ohms.
Now in circuit 1, with two identical batteries and bulbs, the current flowing through the circuit would I = (1.5V+1.5V) / (4ohms+4ohms) = .38 A
Now in circuit 2, with one battery and bulb, the current flowing through the circuit would be I = (1.5V) / (4ohms) = .38A
We know that the amount of current flowing through a light bulb determines its brightness, and thus in circuit 2, .38 A is flowing through 2 bulbs, and in circuit 1 the same amount of current is flowing through only 1 light bulb, thus it is not possible,
Can someone tell me if this is right? Much appreciated.
Here is my question: Is it possible to connect 2 identical batteries to make 2 bulbs connected in series light just as brightly as one bulb connected to one battery?
Reasoning: let's say each battery has a voltage of 1.5V and that each light bulb is equal and has a resistance of 4 ohms.
Now in circuit 1, with two identical batteries and bulbs, the current flowing through the circuit would I = (1.5V+1.5V) / (4ohms+4ohms) = .38 A
Now in circuit 2, with one battery and bulb, the current flowing through the circuit would be I = (1.5V) / (4ohms) = .38A
We know that the amount of current flowing through a light bulb determines its brightness, and thus in circuit 2, .38 A is flowing through 2 bulbs, and in circuit 1 the same amount of current is flowing through only 1 light bulb, thus it is not possible,
Can someone tell me if this is right? Much appreciated.