Battery’s terminal potential difference

AI Thread Summary
The discussion focuses on calculating the terminal potential difference of a 1.5 V AA battery connected to a circuit with a total series resistance of 50 ohms and an internal resistance of 1 ohm. The user correctly applies the formula I = EMF / (R + r) to find the current, resulting in 29.412 mA. They then calculate the terminal voltage as 1.47 V by subtracting the voltage drop across the internal resistance from the EMF. The method used is confirmed as correct, and an alternative approach using the potential divider rule is suggested. Overall, the calculations and methodology are validated by other participants in the discussion.
zohaibtarar
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Homework Statement


An external circuit with a total series resistance of 50 (omega) is connected to a 1.5 V AA battery which has an internal resistance of 1 (omega). What is the battery’s terminal potential difference?

Homework Equations


I = EMF / (R + r)

The Attempt at a Solution


I = EMF / (R + r) = 1.5V/ 51 Ohm = 29.412 mA

V = 1.5V - 0.029412A * 1 Ohm = 1.47 Voltbut i m still confused if i did it right or wrong please help

Thank you!
 
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