Bead on a string, find y(x) if horizontal velocity is const.

AI Thread Summary
The discussion revolves around a physics problem involving a bead on a string where the horizontal velocity is constant. The user is confused about how height changes while maintaining a constant horizontal velocity, questioning the implications of conservation of energy in a frictionless scenario. They speculate that the solution might involve a specific function or shape, like a circle, but remain uncertain about the correct approach. The user seeks guidance on how to relate the vertical velocity to the initial conditions and calculate total velocity at various points along the wire. The conversation highlights the complexities of integrating physics principles to solve for y(x) under the given constraints.
Phantoful
Messages
30
Reaction score
3

Homework Statement


5IgHXYY.png

Homework Equations


K = (1/2)mv2
U = mgh
W=Fd
Integration/Calculus

The Attempt at a Solution


I'm not sure what I should be doing for this question, if height changes how is it possible that velocity stays the same, according to the conservation of energy (frictionless wire)? If horizontal velocity stays the same, then I would assume that some sort of slope would equal 0 of this equation; however the line would be still at y=0, and it says there's an answer besides that. I'm not sure of any other weird functions that could do this, except maybe a circle (but I doubt that's the answer because it's a wire). How should I be solving this?
 

Attachments

  • 5IgHXYY.png
    5IgHXYY.png
    9.2 KB · Views: 694
Physics news on Phys.org
Note that the problem specifies that the horizontal velocity is constant at v0. There is no such constraint on the vertical velocity or the speed.
 
  • Like
Likes Phantoful
Also, given #2, how would you get the total velocity at any given point along the wire? How can you relate that to the initial velocity using some physics principle?
 
  • Like
Likes Phantoful
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top