Beta decay Charge conservation

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SUMMARY

In beta decay, a neutron decays into a proton, an electron, and an antineutrino, illustrating charge conservation. The process involves the conversion of a down quark (charge -1/3) into an up quark (charge +2/3) through the emission of a W- boson. The total charge remains balanced at -1/3 before and after the decay, with the W- boson mediating the interaction. This two-step process can be visualized through a Feynman diagram, which details the quark interactions involved.

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  • Understanding of beta decay processes
  • Familiarity with quark charge properties
  • Knowledge of particle physics terminology, including W bosons
  • Ability to interpret Feynman diagrams
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  • Research the role of W bosons in particle interactions
  • Study Feynman diagrams related to beta decay
  • Explore the conservation laws in particle physics
  • Learn about the differences between beta minus and beta plus decay
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jc09
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In beta decat the u quark fromthe proton and the d quark from the neutron interact to produce a electron and it's neutrino. I'm wondering about the charge conservation of this process because a neutron has zero charge and a proton has charge of 1. How do we end up with a electron charge of -1 at the end.
 
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A neutron decays into a proton, an electron, and a neutrino.
 
jc09 said:
In beta decat the u quark fromthe proton and the d quark from the neutron interact to produce a electron and it's neutrino. I'm wondering about the charge conservation of this process because a neutron has zero charge and a proton has charge of 1. How do we end up with a electron charge of -1 at the end.

You should look for a Feynman diagram of this process showing the quark lines
 
If a neutron has zero charge and produces a proton charge one and a electron charge -1 and a neutrino charge 0 why does it need a W- to mediate this
 
In \beta^- decay, a down quark (charge -1/3) converts to an up quark (charge +2/3), an electron (charge -1) and an antineutrino (charge 0). The total charge is -1/3 before and after. Introducing a virtual W boson, we have a two-step process:

d \rightarrow u + W^-

W^- \rightarrow e^- + \bar \nu_e
 
Last edited:

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