- #1
higginsdj
- 25
- 0
Hi, my math and physics are poor so please bear with me.
I have an bifurcated asteroid - 2 components. A sphere diameter 1.5km (m1) and a larger sphere, 2km in diameter (m2). The spheres are touching. System spins around the long axis.
Assuming both bodies have internal strength (not gravitationally bound rubble piles), I need to calculate the systems spin rate at which point the bodies separate for varies densities.
Now I know the physics:
Fcentrigual = 4 Pi^2 r / P ^2 (P is spin rate in seconds)
Fgravity = G * (4/3 * Pi * Rm1^3 * rho)*(4/3 * Pi * Rm2^3 * rho) / r^2 (rho = density)
Now in a large system (someone on the surface of earth) r is easy but in a system as described above, what is r? Is it the distance from the systems centre of rotation to the interface between the 2 bodies or the centre of the system to the centre of the sphere component? Does this apply to both calculations or is the measure of r different for each?
Cheers
David
I have an bifurcated asteroid - 2 components. A sphere diameter 1.5km (m1) and a larger sphere, 2km in diameter (m2). The spheres are touching. System spins around the long axis.
Assuming both bodies have internal strength (not gravitationally bound rubble piles), I need to calculate the systems spin rate at which point the bodies separate for varies densities.
Now I know the physics:
Fcentrigual = 4 Pi^2 r / P ^2 (P is spin rate in seconds)
Fgravity = G * (4/3 * Pi * Rm1^3 * rho)*(4/3 * Pi * Rm2^3 * rho) / r^2 (rho = density)
Now in a large system (someone on the surface of earth) r is easy but in a system as described above, what is r? Is it the distance from the systems centre of rotation to the interface between the 2 bodies or the centre of the system to the centre of the sphere component? Does this apply to both calculations or is the measure of r different for each?
Cheers
David
Last edited:
