A billiard ball of mass [tex] m_{A}=0.400kg [/tex] moving with a speed [tex] v_{A} =1.8m/s[/tex] strikes a second ball, initially at rest, of mass [tex] M_{B}=0.500kg[/tex]. As a result of the collision, the first ball is deflected off at an angle of [tex]30\deg[/tex] with a speed of [tex]v'_{A}=1.1 m/s[/tex].(adsbygoogle = window.adsbygoogle || []).push({});

a) taking the x-axis as the positive direction of motion of ball A, write down the equations expressing the conservation of momentum for the components in the x and y directions seperatley.

B)Solve the equations for the speed, [tex] v'_{B}[/tex], and the angle, [tex]\theta'_{2}[/tex] of ball b. Do not assume the collision is elastic.

my work

[tex]equations[/tex]

[tex]m_{A}v_{A}=m_{A}v'_{A}\cos\theta'+ m_{B}v'_{b}\cos\theta'_{2}[/tex]

[tex]0=m_{A}v'_{A}\sin\theta'+m_{B}v'_{b}\sin\theta'_{2}[/tex]

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# Billiard ball Momentum help

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