Binomial Coefficient Equivalency

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Find an expression that is identical to \sum_{k=0}^n \binom{3n}{3k}

According to Wolfram, the correct solution to this is: \frac{1}{3} \left(2(-1)^n + 8^n\right)

But I'm not sure which identities of the binomial coefficient I'm supposed to use to prove this. Can anyone give me some direction?

Thanks!
 
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Does nobody have any ideas? I was wondering if it were possible to confirm Wolfram's answer via induction, but expanding the resulting binomial coefficients fron the n-1 to the n case is proving to be fairly difficult. Any help is appreciated.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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