Binomial Probability problem.

[TheHamburgler1]

Homework Statement

10% of engines manufactured on an assembly line are defective. If engines are randomly selected one at a time and tested, what is the probability that the first defective engine will be found between the 5th trial and the 25th trial, inclusive?

Homework Equations

The Attempt at a Solution

I believe this is just a binomial distribution with Bin(n,1) where n varies between 5 and 25.

\sum(nC1)(0.1)(.9)^(n-1)

This is way off because I am getting 6.47...

thanks ahead of time.

 

[tiny-tim]

Hi TheHamburgler1!

No, it's just P(first is defective is the 5th) + … + P(first is defective is the 25th)

 

[TheHamburgler1]

Hi TheHamburgler1!

No, it's just P(first is defective is the 5th) + … + P(first is defective is the 25th)

Would we not express each of those via Bin(n,.1) where x=1? If not, how would we express one of them?

Thanks

 

[TheHamburgler1]

Actually, this could be a Geometric distribution problem right? In that case we would sum x from 5 to 25 of (.1)(.9)^(x-1). This gives 0.5843102

 

[tiny-tim]

(just got up :zzz: …)

Actually, this could be a Geometric distribution problem right? In that case we would sum x from 5 to 25 of (.1)(.9)^(x-1).

Yup!

(and I assume you've used algebra to calculate that, and not 20 additions? )