Binomial (Properties of Coefficients)

ritwik06
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Homework Statement


\sum^{n}_{r=0} (2r+1) (^{n} C_{r})^{2}


The Attempt at a Solution


x(1+x^{2})^{n}
If I differentiate this and put x=1;
I will get the above series without the squares of the binomial coefficients.Will multiplying by (1+x)^{n} help now?
 
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The "problem" you give is a polynomial. Now, what are you supposed to do with it? What is the question?
 
I have to prove this equal to anyone of these.
<br /> a) (2n+2) ^{2n} C_{n} <br />

<br /> b) (n+1) ^{2n} C_{n} <br />

<br /> c) (2n+1) ^{2n} C_{n} <br />

<br /> d) (n) ^{2n} C_{n}<br />
 
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Help me!
 
Well to make things easier (and to cheat a little), let n=2, for example. You should find that only (b) holds. Now of course a proof is required, so that itself doesn't count. But at least you know where to focus your effort.
 
Defennder said:
Well to make things easier (and to cheat a little), let n=2, for example. You should find that only (b) holds. Now of course a proof is required, so that itself doesn't count. But at least you know where to focus your effort.

The answer was already given to me in the textbook. I am just wondering how to prove the result...
 
Roughly the same trick as the other one. Replace r in 2r+1 by n-r. As for C(n,r)^2, That's the same as C(n,r)*C(n,n-r). If you sum of over r, isn't that the same as the number of ways to choose n objects from a group of 2n objects?
 

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