BJT Biasing - Simple easy 1 minute answer

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    Biasing Bjt
AI Thread Summary
In the discussion on BJT biasing, the main focus is on calculating the currents and voltages for an NPN transistor circuit with given parameters. The user questions whether the emitter current (IE) is zero when the emitter resistor (RE) is 0 ohms. It is clarified that RE being 0 ohms does not mean IE is zero, as it is still calculated using the relationship IE = IB + IC. The user confirms their understanding that this equation is applicable for determining IE. The conversation emphasizes the importance of correctly applying the fundamental equations in transistor analysis.
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Homework Statement


Find IB, IC, IE, VCE, VBC, and VEB for the NPN transistor in the circuit below for β = 50, 150, 500. Let VCC = 10 V, R1 = 100 KΩ, R2 = 400 KΩ, RC=2 KΩ, and RE = 0 Ω. Assume VBE = 0.7V.

Homework Equations



V = iR
IE = Ib + Ic

The Attempt at a Solution



My question is that if RE = 0 ohms, then is Ie automatically 0 amps?

But the how does Ie = Ib + Ic apply? Because I got 92.25uA for Ib and 4.56mA for Ic?

Help! :]
 
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Forgot to put the figure :]
 

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ally34 said:
My question is that if RE = 0 ohms, then is Ie automatically 0 amps?
No. A piece of connecting wire from emitter to ground = 0 Ω :smile:
 
NascentOxygen said:
No. A piece of connecting wire from emitter to ground = 0 Ω :smile:


Awwww!

:[ So Ie = Ib + Ic is correct?

I would use this to calculate Ie?
 
ally34 said:
Awwww!

:[ So Ie = Ib + Ic is correct?
Yes.

I would use this to calculate Ie?
It is involved in the calculations.
 

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