Preface: I understand that regardless of any further details, the correct answer is "No, it does not, because..." I'm looking for an answer because clearly I don't understand something about either thermodynamics, mirrors, or black body radiation. In my mind, the scenario I describe follows the rules of black body radiation and mirrors to violate the second law of thermodynamics. This is almost certainly incorrect, so I need someone to tell me what I'm getting wrong. Scenario: Imagine you have a 1 meter long and 200 cm wide aluminum parabola with a 99% reflective mirrored surface on the inside. Suppose the outside of the parabola has been blackened by a laser. To keep this mentally simple, let's get rid of convection by placing this mirror in a chamber with a near-perfect vacuum, and let's get rid of conduction by placing the chamber and mirror on the international space station so that the mirror can stay in the middle of the chamber without touching anything. Assuming you don't change the temperature of the chamber, the mirror and chamber should (presumably) reach an equilibrium at room temperature. Problem: The mirror will produce black-body radiation. However, most of the black-body radiation emitted from the inside of the parabola will be reflected in a single direction, towards the chamber. This means that the parabola will be emitting directed energy which heats up one side of the chamber. We should be at thermodynamic equilibrium, but we're not. What's going on here?