Block of ice melts - entropy of ice?

AI Thread Summary
The discussion focuses on calculating the change in entropy for a 2.00 kg block of ice melting at 0.0˚C. Initially, an incorrect approach using the temperature change was proposed, but it was pointed out that the temperature remains constant during the melting process. The correct method involves using the latent heat of fusion, leading to the calculation of Q as 667.4 kJ. This value is then used to determine the change in entropy, ensuring accurate results. The conversation emphasizes the importance of using the appropriate equations for phase changes in thermodynamics.
ally1h
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Homework Statement


A 2.00 kg block of ice at 0.0˚C melts. What is the change in entropy of the ice as a result of this process?


Homework Equations


Q = mcΔT
ΔS = Q/T



The Attempt at a Solution


Q = (2.00 kg)(2.1 kJ/kg*K)(273 K)
Q = 1092 J

ΔS = 1092 J / 273 K
ΔS = 4 J/K


Any good?
 
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Not good. Why would you calculate Q using an equation with ΔT? The temperature change is zero, not 273 K. I like your second equation, though, which assumes constant temperature.

How about getting the energy from the phase change?
 


Then I'm not sure how to do the problem, the first part anyway, because then Q = 0 and if Q = 0 then ΔS = 0 as well...
 


How about looking up the energy associated with the phase change?
 


Ahhh... so I'm looking at latent heat then?
Q = mass x latent heat of fusion
Q = (2.00 kg)(333.7 kJ/kg)
Q = 667.4 kJBetter? And then plug that into the second equation?
 


Better.
 
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