Block, Ramp, Friction, and Spring Due Tomorrow

AI Thread Summary
The discussion revolves around a physics homework problem involving a block being pulled up an incline. The key points include calculating the work done by the man pulling the block, which is confirmed to be 513.45 J. The participant struggles with finding the block's speed upon reaching a horizontal surface after sliding down the incline, using the work-energy theorem for calculations. They attempted to determine the height and speed but encountered difficulties in correctly applying the equations. The conversation highlights the importance of accurately accounting for gravitational potential energy and friction in the calculations.
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Block, Ramp, Friction, and Spring Due Tomorrow!

Homework Statement



A man pulls a block of mass m = 17 kg up an incline at a slow constant velocity for a distance of d = 3.5 m. The incline makes an angle q = 33° with the horizontal. The coefficient of kinetic friction between the block and the inclined plane is µk = 0.4.
a) What is the work Wm done by the man?

Wm = 513.45J OK

HELP: Draw a free-body diagram of the block.
At the top of the incline, the string breaks and the block, assumed to be at rest when the string breaks, slides down a distance d = 3.5 m before it reaches a frictionless horizontal surface. A spring is mounted horizontally on the frictionless surface with one end attached to a wall. The block hits the spring, compresses it a distance L = 0.6 m, then rebounds back from the spring, retraces its path along the horizontal surface, and climbs up the incline.

b) What is the speed v of the block when it first reaches the horizontal surface?

v = m/s

HELP: Use the work-energy theorem.
HELP: What is the work done on the block by gravity? What is the work done on the block by friction? The sum of these two numbers will equal the kinetic energy of the block at the bottom of the incline.

c) What is the spring constant k of the spring?

k = N/m

d) How far up the incline d1 does the block rebound?

d1 = m



So I am stuck on part b)
Here's what I did:

Homework Equations


KE=PE - Wf= mgh - mumgcosq.
KE=1/2mv^2
so, v=sqrt(2KE/m)=sqrt(2(gh-mugcosq)

The Attempt at a Solution


To calculate h I tried sinq=h/d so h=dsinq= 3.3

I plugged this in and got v=sqrt(2(9.81*3.3-.4*9.81*cos33))= 5.5m/s
I also tried to add PE and Wf. What am I doing wrong?
 
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I got a similar question. For part b I tried v = sqrt 2(gh- ug cos 33). It should work however I'm having trouble w/ it.
 
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