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Bode plot application

  1. Jun 24, 2016 #1
    Hello,
    After long time i am able to find Laplace transform function but cant understand the bode plot which give information of frequency response and magnitude i think
    plaese anyway here how can push my thinking ahead in it?
     
  2. jcsd
  3. Jun 24, 2016 #2

    anorlunda

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    https://en.m.wikipedia.org/wiki/Bode_plot

    You can't get a whole semester course from an online forum. I suggest that you try hard to understand the wiki article linked. After that, you can return here with more specific questions and we will try to help.
     
  4. Jun 24, 2016 #3
    ok, there is function s+1/s+2

    how to draw bode plot?
    i was not able to understand at that time.


    Bode_High-Pass.PNG
     
  5. Jun 24, 2016 #4

    LvW

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    Should both diagrams be correlated?
     
  6. Jun 24, 2016 #5
    no because one show for phase and another show for magnitude.
     
  7. Jun 24, 2016 #6

    LvW

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    Sorry - but this is not an answer to my question (I did not ask if both are "equal").
    The complete BODE diagram for each frequency dependent network consists of TWO drawings: (a) Magnitude vs. frequency and (b) phase vs. frequency.
    You have shown two such diagrams - however, it seems that they are not for the same circuit (because the must be correlated!).
     
  8. Jun 24, 2016 #7
    i have no idea get it from wiki.
    any way how they should be correlated..
     
  9. Jun 24, 2016 #8

    LvW

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    As I wrote already: Each frequency-dependent circuit (most simple example: RC lowpass) can be split into a magnitude and a phase function.
    That is pure mathematics: H(jω)=|H(ω)|*exp(φ(ω)).
    So you have two functions which are, of course, correlated because they come from the same circuit.
     
  10. Jun 25, 2016 #9
    how to learn bode plot??
     
  11. Jun 25, 2016 #10

    LvW

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    Simple answer: Learn how to produce a graphical representation of magnitude and phase of a simple frequency-dependent network (R-C combination).
    Start with H(jw)=Vout/Vin and calculate magnitude and phase functions. This requires some basic math knowledge.
     
  12. Jun 25, 2016 #11
    i have got Vo/Vi=s+1/s+2
     
  13. Jun 25, 2016 #12

    LvW

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    I suppose you mean (s+1)/(s+2), correct?
    * Do you know the meaning of "s"?
    * Are you able to write down the expressions for magnitude and phase?
     
  14. Jun 25, 2016 #13
    after that i dnt not no please teach me after what is s and s=jw may be zero poles
    no i frget i will remijnd if you follow
     
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