Engineering Bode plot for active low pass filters

AI Thread Summary
The discussion focuses on creating Bode plots for active low-pass filters using transfer functions. Participants emphasize that the plots can be sketched by hand without needing specific resistor or capacitor values, as the essential characteristics are defined by the critical frequency and gain. It is suggested to use logarithmically spaced frequencies to illustrate the gain and phase responses accurately. The importance of understanding the shape of the Bode plot and the significance of the 3dB point is highlighted. Ultimately, a hand-drawn sketch suffices for demonstrating comprehension of the filter's behavior.
peasngravy
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Homework Statement
Derive a transfer function for each of the filter circuits and sketch a bode plot
Relevant Equations
Av = Vout/Vin
Hi

Can anyone help with this? I understand what the bode plots should look like but I am not sure how to produce a plot in excel for them without any values

The transfer functions are:

Vout/Vin = 1/(SQRT(1+(ω/ωc)^2)
and
Vout/Vin = -G/(1+j(ω/ωc))

As both are first order filters they will have a roll-off of 20db per octave
1607457378973.png1607460211644.png

Thanks!

edited to add transfer function screenshot (still no good with Latex :) )
 
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peasngravy said:
As both are first order filters they will have a roll-off of 20db per octave decade
:smile:

What kind of plots have you done in Excel before? Also, have you downloaded a free copy of LTSpice yet? That can be a good way to check your work, plus it's a good skill to learn to be comfortable simulating circuits in Spice.
 
peasngravy said:
I am not sure how to produce a plot in excel for them without any values
You need to select a number of appropriate frequencies and calculate the gain (in dB) and the phase (typically degrees) for each frequency. Plot the results using linear (gain, phase, vertical axis) and log (frequency, horizontal axis) to show the "straight lines". Be sure to select frequencies above and below the 3dB frequencies - say plus and minus two decades as below..

As the frequency is plotted on a log axis it is useful to choose, say, four "logarithmically-equally-spaced" frequencies per decade as 1.78, 3.16, 5.62 and 10 Hz.

See Bode Plot in wiki.

If you must use Excel try a Google search with bode plot excel

bode.png
 
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It is common, when values aren't given, to plot these after normalizing the frequency. You can define the normalized frequency ωn = ω/ωc, then you generate values of ωn around 1 to plot the filter response. Then label your frequency axis "ω/ωc".
 
Do I just make up values for the resistors and capacitors though? I don't understand how to calculate the gain at a certain frequency without replacing the values in the transfer function with actual numbers?
 
You have the transfer functions which you need to plot.

You don't need R1 and R2 because you are told G = R1/R2. G is therefore a scaling factor on the Gain axis - label it 1G, 2G, 3G etc.

You don't need C because you have ω/ωc. = see DaveE's post.

It says "sketch a bode plot" so do it by hand labelling the axes to show the 3dB point. You don't need Excel.

The question is testing your understanding of the shape of a Bode plot and the importance of the 3dB frequency.

Every circuit with a 3dB breakpoint and 20 dB/decade fall off has the identical shape Bode plot.

It is only the markings on the axis which change with different circuits. One circuit, say, has a 3dB point at 10kHz and a gain of 35dB; another circuit, say, has a 3dB point of 27MHz and a gain of 19dB. The Bode plots are identical - only the markings on the axes are different.

So the question is solved by

a) sketch a generic Bode plot - without axis markings they are all identical
b) now mark the axes with the graduations for the specific circuit

In my example plots, replace 100 by ωc, 1000 by 10ωc and 10000 by 100ωc.
 
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Ok thank you - I had actually already sketched it by hand and asked my lecturer if this was enough, but he didn't reply and I assumed that meant he was unhappy with the question :D

I will go with the hand sketch as I know how they should look anyway. Thanks everyone for your time.
 
peasngravy said:
asked my lecturer if this was enough, but he didn't reply and I assumed that meant he was unhappy with the question
Not a great assumption. He may have just been occupied with other things. Give the guy a break, he has other things to do too.
 
Yeah maybe but this was 2 weeks ago :biggrin:

No big deal anyway and it's not like I harassed him or anything, just asked him and moved on when he didn't reply.
 
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peasngravy said:
I will go with the hand sketch as I know how they should look anyway.
Please let us know how you get on so that if my advice of sketching was bad :frown: I don't give it again.

In principle, I think what the question is aiming at is trying to get you to see what is important and what isn't. A simple low pass filter is characterised by:

- a flat gain response up to a given critical frequency
- a straight line (on a log/linear graph) falling at 20 dB/decade beyond the critical frequency (so be sure to plot frequency on a log scale!)
- a 3dB drop in gain at the critical frequency
- a 45 degree phase shift at the critical frequency.

Hence the circuit is completely characterised by only two things: the critical frequency and the gain.
 
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