Boiling points and hydrogen bondings

AI Thread Summary
The boiling points of hydrogen halides are influenced by hydrogen bonding and molecular size. HF has the highest boiling point at 20°C due to strong hydrogen bonds, while HCl, HBr, and HI have significantly lower boiling points at -85°C, -67°C, and -35°C, respectively. The expected order of boiling points based on molecular weight does not hold because of the stronger intermolecular forces in HF compared to the others. As molecular size increases down the group, van der Waals forces become more significant, affecting boiling points. Understanding these trends requires considering factors like electronegativity, dipole moments, and the number of electrons in the atoms.
kasse
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Homework Statement



Explain the boiling points of HF, HCl, HBr nd HI


The Attempt at a Solution



The boiling points are:

HF: 20 C
HCl: -85 C
HBr: -67 C
HI: -35 C

The hydrogen bondings between H and F are stronger than other hydrogen bondings. Therefore HF has the highest boiling point. But then I'd expect the order to be HCl > HBr > HI; not the opposite. How can that be explained?
 
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do H-bonds really occur in all the hydrogen halides? what are the requirements for an H-bond to be formed?
 
kasse said:

Homework Statement



Explain the boiling points of HF, HCl, HBr nd HI


The Attempt at a Solution



The boiling points are:

HF: 20 C
HCl: -85 C
HBr: -67 C
HI: -35 C

The hydrogen bondings between H and F are stronger than other hydrogen bondings. Therefore HF has the highest boiling point. But then I'd expect the order to be HCl > HBr > HI; not the opposite. How can that be explained?

This is somewhat of a trick question you really need to observe the relations between the intermolecular and intramolecular-what's especially important here is the polarizability with additional regard to dipole moments due to electronegativity- attractions in this case.
 
Kushal said:
what are the requirements for an H-bond to be formed?

No idea. My book only says that H-bonds occur between molecules when a H-atom bonds with an electronegative atom.
 
it should've been said 'a VERY elctronegative atom'. only N, O and F can form H-bonds. does this help you?!
 
Yes, thanks.
 
i was more expecting you to explain the trends in boiling point using this information than saying thanks.

:)
 
This is actually a very hard trick question. I know I had some problem with it in the first chem-course at my university. But, it is a very multifaceted question. And also a rather tricky one, because many factors play their part in a complex thing like boiling points. Dipole-momentum, electronegativity, bond-lengths and such. But one thing that often is overlooked and why this is a hard question is about the quantum number, the amount of shells and electrons in the atom.

When a atom has a lot of electrons, they also increase the the amounts of van-der-waalforces in the molecule. And if the amount goes up for a given timeperiod, the strength of the bond also goes up.

Which means that downward in the halide-group, you always get stronger bonds (van-der-waals) due to larger molecules. This is something you can generalize on the atomic table and periods. But remember, that it is a lot of exceptions to this rule. Which is why chemistry is a bit tricky.
 
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