Bonding force of an optical electron and the nucleus of ion Cr3+

[gmentat]

Does anybody know how to find bonding force of an optical electron and the nucleus of ion Cr3+ (in pink ruby during normal and excited states (excitement of light))?

And also how to find the magnetic moment of the same electron during EPR (during excitement by a radiowave)? Condition of the resonance is: Intensity = 3.6 kGs and Frequency = 9.4 GHz (in normal and excited states).

Thanks for any suggestions!

 

[alxm]

The http://physics.nist.gov/PhysRefData/ASD/index.html" .

 

[gmentat]

Thanks for the link alxm. Can you give a clue how to find this value in the database? I'm not a physicist...

 

[alxm]

Well you enter "Cr III" and you get your spectral lines, or levels, depending on which database you look in. I believe it has relative g-factors as well.

The magnetic moment is always the same (\mu_B), it's the http://en.wikipedia.org/wiki/Landé_g-factor" that differs between levels/atoms. Given your g-factor, field strength and frequency, you have:
h\nu = g_\mathrm{e} \mu_B B_\mathrm{eff} = g_\mathrm{e} \mu_B B_0 (1 - \sigma)

Where B_{eff} is the effective field, since the atom's environment (chemical bonds, if it's in a molecule, etc) is going to influence the field, which you can also express with the number \sigma. (If it didn't change with environment, EPR wouldn't be much use in analyzing chemical structure)

You might have to look into the literature to find relevant values for your g-factors, etc.