Boolean Simplification: Steps and Example for (A+B)(A+B)= X

[cact]

I was just wondering if someone could check my answer for simplifiying the below question.

\bar{(A+B)}(A+B)= X the first (A+B) has a continuous bar above it from bracket to braket.


Would this be the correct way to simplifiy it?
(\bar{A}*\bar{B}) + (A+B)= X

\bar{A}A\bar{B}+A\bar{B}B= X

(0)\bar{B}+A(0)= X

A\bar{B}= X

be the correct steps to simplifiy the problem?

 

[maverick280857]

If only the first bracket has the bar over it then there seems to be a mistake in the first step. The sum can be converted into the product using deMorgan's Laws but you can do so only for the expression under the bar. So,

\vec{A+B} = \vec{A}\vec{B}

Now do this all over and you should be through (the brute force method after the first step in most problems isn't a bad idea unless you observe some symmetry or vanishing terms...)

 

[wais]

Yes, your steps for simplifying this Boolean expression are correct. Let's break them down to better understand the process of Boolean simplification.

Step 1: Distributive Property
The first step is to apply the distributive property, which states that for any two variables A and B, (A+B)(A+B) can be simplified to A*A + A*B + B*A + B*B. In this case, A*B and B*A can be simplified to AB, since order does not matter in Boolean algebra. This gives us (A+B)(A+B) = A*A + AB + AB + B*B.

Step 2: Complement Property
Next, we can use the complement property, which states that A*\bar{A} = 0 and A+\bar{A} = 1. In this case, we can simplify A*A and B*B to 0, since they are complements of each other. This leaves us with 2AB = X.

Step 3: Simplify
Finally, we can simplify further by dividing both sides by 2, giving us AB = X/2. This is the simplest form of the expression, and is equivalent to the original expression \bar{(A+B)}(A+B).

So, your steps of simplification are correct and you have arrived at the correct simplified expression. Good job!