Bose-Einstein condensate of photons

In summary, the conversation discusses whether a photon number state of n photons in the same mode can constitute a Bose-Einstein condensate (BEC) of photons. It is agreed that this is not possible since a photon gas can never reach the necessary low temperature for BEC due to the decrease in photon number as it is cooled. However, there are controversial publications regarding photon BEC at room temperatures, but it is argued that these are not true BECs due to lack of coherence. The conversation also delves into the theoretical justification for this and the role of equilibrium. It is noted that a BEC can only be achieved in the thermodynamic limit with a constant particle density. Additionally, there is a disagreement over whether the polar
  • #1
phonon44145
53
0
Does the photon number state of n photons in the same mode (i.e. Fock state |n>) constitute a Bose-Einstein condensate of photons?
 
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  • #2
No. For a closed system of bosons with a finite mass the number of particles is fixed, and if it is cooled eventually a critical temperature Tc is reached below which a finite fraction of them are forced to occupy the ground state. But if you cool a photon gas the number of photons simply decreases and Bose-Einstein condensation never occurs.
 
  • #3
Bill_K said:
But if you cool a photon gas the number of photons simply decreases and Bose-Einstein condensation never occurs.

Is that necessarily so? Last year the group aroun Martin Weitz from the university of Bonn had two high-profile publications on a photon-number conserving way of thermalizing a photon gas and on photon BEC (Nature Phys. 6, 512 (2010) and Nature 468, 545 (2010)).

I mean, these publications sure are pretty controversial, but just stating it never occurs without detailed discussion is pretty harsh.

Just to be clear, I would like to stress and support the opinion that it is indeed true that a photon number Fock state of course does not constitute a BEC.
 
  • #4
But is there a physical explanation for this? I thought the low temperature requirement for BEC was only caused by the need to achieve sufficient overlapping of de Broglie waves. In principle, if you take a large photon number state |n>, all photons being in the same mode, it seems that the mere concentration of photons should provide for a substantial overlap? And isn't it true that low temperature of a photon gas just means we imitate the black body spectrum at low T, that is, go to the infrared/RF range?
 
  • #5
The necessary temperature for condensation indeed depends on the mass of the particles. For examples there are proposals to create polariton condensates at room temperatures and already demonstrations of that for temperatures way above 100K.

A photon number state is not a BEC because it will lack coherence. If you take for example Legett's book on quantum fluids, you will see that you also need off-diagonal long-range order, which roughly translates into long-range spatial coherence or a fixed phase relationship over larger distances. This is not necessarily realized for a realistic photon number state (remember photon number-phase uncertainty). It is realized for a completely delocalized photon number state, but these are pretty theoretical constructs, as far as I know.
 
  • #6
Cthugha said:
It is realized for a completely delocalized photon number state, but these are pretty theoretical constructs, as far as I know.

For example, in a real laser (whose output is essentially coherent)?
 
  • #7
Lasers emit coherent states, which are not Fock states. Coherent states have a Poissonian photon number distribution around some mean photon number as indicated by a g2 of 1. Fock states have a g2 of 1-(1/n) where n is the photon number.
 
  • #8
The important point with a BEC being a BEC is that it has to be an equilibrium state at some (low) temperature. A laser is not an equilibrium state.
The Photon BEC described by Martin Weiz is not a condensate of free photons but rather of photons interacting with matter, i.e. polaritons.
 
  • #9
Cthugha said:
A photon number state is not a BEC because it will lack coherence. If you take for example Legett's book on quantum fluids, you will see that you also need off-diagonal long-range order, which roughly translates into long-range spatial coherence or a fixed phase relationship over larger distances. This is not necessarily realized for a realistic photon number state (remember photon number-phase uncertainty). It is realized for a completely delocalized photon number state, but these are pretty theoretical constructs, as far as I know.

Off diagonal long range order can also be realized in states with fixed particle number. E.g. any condensate of atoms contains a fixed number of atoms. A description in terms of phase eigenstates merely simplifies the mathematical description. Anyhow a BEC is strictly defined only in the thermodynamical limit when N goes to infinity and the density N/V is constant. Then it makes little difference to distinguish between states with infinitely but fixed number of particles and infinite but unsharp number of particles.
 
  • #10
Bill_K said:
No. For a closed system of bosons with a finite mass the number of particles is fixed, and if it is cooled eventually a critical temperature Tc is reached below which a finite fraction of them are forced to occupy the ground state. But if you cool a photon gas the number of photons simply decreases and Bose-Einstein condensation never occurs.
What's the theoretical justification for this? Is it theoretically impossible for the amount of photons to stay the same but for their frequency to decrease? Maybe because of momentum concerns?
 
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  • #11
DrDu said:
The important point with a BEC being a BEC is that it has to be an equilibrium state at some (low) temperature. A laser is not an equilibrium state.
The Photon BEC described by Martin Weiz is not a condensate of free photons but rather of photons interacting with matter, i.e. polaritons.

Weitz himself strongly opposes that point of view. To enter the polariton regime, interaction with matter is not enough, but you need strong coupling (or in the semiclassical regime non-perturbative coupling) between the light field and matter excitations which amounts to reversible spontaneous emission. I am quite sure that is not the case in the Weitz-paper as scattering rates are too small and he operates in the weak coupling regime. That of course does not mean no coupling and it should indeed be stressed that these are not free photons, but cavity photons. The question is rather whether he found a good way to have a "masked" common laser. I personally also do not like that paper too much, but mostly because of the double standards it shows in refereeing. Compared to the amount of data that was required to get the first serious paper on polariton condensation by Kasprzak published, the evidence for the photon BEC provided by Weitz and his coworkers is tiny. No g2 measurements, not much about first-order coherence,...

The role of equilibrium is also a bit more complicated as has been pointed out in terms of "steady-state" polariton condensation. The most thorough discussion I am aware of comes from the group of Peter Littlewood (M. H. Szymańska, J. Keeling, and P. Littlewood, "Mean-field theory and fluctuation spectrum of a pumped decaying Bose-Fermi system across the quantum condensation transition", Phys. Rev. B 75 195331 (2007)) with the basic result that any distribution function diverging at the chemical potential can cause instability of the normal state and the onset of condensation. I do not watch this branch of theory too closely, but I am quite sure they stepped beyond mean-field in the meantime.

DrDu said:
Anyhow a BEC is strictly defined only in the thermodynamical limit when N goes to infinity and the density N/V is constant.

Sure. However, the number of real systems showing BEC in the strictest sense will amount pretty much to zero.

DrDu said:
Off diagonal long range order can also be realized in states with fixed particle number.
Yes, but for particles which vanish upon detection like photons this is somewhere between very hard and impossible to achieve. It is easier for atoms.
 
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  • #12
Cthugha said:
Weitz himself strongly opposes that point of view. To enter the polariton regime, interaction with matter is not enough, but you need strong coupling (or in the semiclassical regime non-perturbative coupling) between the light field and matter excitations which amounts to reversible spontaneous emission. I am quite sure that is not the case in the Weitz-paper as scattering rates are too small and he operates in the weak coupling regime. That of course does not mean no coupling and it should indeed be stressed that these are not free photons, but cavity photons. The question is rather whether he found a good way to have a "masked" common laser.

Yes, I agree on that. Whether the photons are merely non free or polaritons in sensu stricto is however secondary in my oppinion. The important point is that their dispersion relation is changed so as to render them effectively massive.
 

1. What is a Bose-Einstein condensate of photons?

A Bose-Einstein condensate of photons is a state of matter where a large number of photons, the fundamental particles of light, are in the same quantum state and behave like a single macroscopic particle.

2. How is a Bose-Einstein condensate of photons created?

To create a Bose-Einstein condensate of photons, a dilute gas of photons must be cooled to extremely low temperatures, close to absolute zero. This causes the photons to lose their individual identities and form a collective state.

3. What are the properties of a Bose-Einstein condensate of photons?

A Bose-Einstein condensate of photons exhibits unique properties such as coherence, where all the photons are in phase with each other, and superfluidity, where the photons can flow without any resistance.

4. What is the significance of a Bose-Einstein condensate of photons?

Bose-Einstein condensates of photons have potential applications in quantum computing, optical communications, and precision measurement. They also provide a platform for studying quantum phenomena and testing fundamental physics theories.

5. How are Bose-Einstein condensates of photons different from other types of condensates?

Bose-Einstein condensates of photons are unique as they are created from particles with no mass and do not require the use of external forces or confinement to form. This distinguishes them from other types of condensates, such as Bose-Einstein condensates of atoms or excitons.

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